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2 years ago

What are the rarefaction and compression regions of a guitar string

Physics

1 answer:

andrezito [222]2 years ago

3 0

Answer:

The middle and end of the string respectively

Explanation:

Rarefaction means region of maximum displacement and compression means region of minimum displacement, hence.

We expect a maximum displacement at the middle of the string because it is said to vibrate greatest at this point and conversely vibrate least at the end point which is the region of compression.

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Some good estimates about the human body can be made if it is assumed that we are made mostly of water. The mass of a water mole

Bezzdna [24]

Answer:

Explanation:

Given

mass of water molecule $m=2.99\times 10^{-26}\ kg$

mass of person $M=62\ kg$

It is given that body is mostly made up of water

suppose n water molecules constitutes 62 kg

so $n\times m=M$

$n=\frac{62}{2.99\times 10^{-26}}$

$n=20.73\times 10^{26}\ kg$

6 0

2 years ago

The lowest possible frequency that can form in a musical instrument is called the _____. A fundamental frequency B the harmonic

NeX [460]

Perhaps D. if it is the lowebsr possible frequency then it would most likely be the last. I may not be 100 percent right, but that's just an educated guess.

5 0

3 years ago

How much heat is absorbed by 60g of copper when it is heated from 20°C to 80°C

nexus9112 [7]

Answer:

I HOPE THIS IS CORRECT

Explanation:

It is heated from 20°C to 80°C. We need to find the heat absorbed. It can be given by the formula as follows : So, 1386 J of heat is absorbed.

7 0

2 years ago

In an experiment conducted using the Young's double-slit apparatus, the separation between the slits is 20 µm. A first-order con

jeka57 [31]

To solve this problem, we use the formula
λ = s sin θ
where s is the separation and θ is the angle interference
So,
λ = 20 x 10^-6 sin 2.5
λ = 8.72 x 10^-7 m

The required angle for the fourth order bright fringe is
θb = sin⁻¹ (4λ / s) = sin⁻¹ (4 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 10.04°

The required angle for the fourth order dark fringe is
θd = sin⁻¹ (4.5 λ / s) = sin⁻¹ (4.5 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 11.31°

6 0

2 years ago

The eyepiece of a compound telescope has a focal length of 12 cm and the objective lens has a focal length of 16 m. What is the

olasank [31]

Answer:

The magnification is 133X

Explanation:

For a refractor telescope using convex lenses, the overall magnification os calculated as by dividing the focal length of the objective by that of the eyepiece.

$M = \frac{f(obj)}{f(eye)}$

So:

$M = \frac{16 m}{12 cm}$

Care must be taken with the units, in this case they are in meters and centimeters, they should be converted into the same unit before calculating:

$M = \frac{16 m}{0.12 m} = 133$

3 0

3 years ago