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Ksenya-84 [330]
3 years ago
11

What are the rarefaction and compression regions of a guitar string

Physics
1 answer:
andrezito [222]3 years ago
3 0

Answer:

The middle and end of the string respectively

Explanation:

Rarefaction means region of maximum displacement and compression means region of minimum displacement, hence.

We expect a maximum displacement at the middle of the string because it is said to vibrate greatest at this point and conversely vibrate least at the end point which is the region of compression.

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A 3250-kg aircraft takes 12.5 min to achieve its cruising
scoundrel [369]

Answer:

effeciency n = = 49%

Explanation:

given data:

mass of aircraft 3250 kg

power P = 1500 hp = 1118549.81 watt

time = 12.5 min

h = 10 km = 10,000 m

v =85 km/h = 236.11 m/s

n = \frac{P_0}{P}

P_o = \frac{total\ energy}{t} = \frac{ kinetic \energy + gravitational\ energy}{t}

kinetic energy= \frac{1}{2} mv^2  =\frac{1}{2} 3250* 236 = 90590389.66 kg m^2/s^2

kinetic energy = 90590389.66 kg m^2/s^2

gravitational energy = mgh = 3250*9.8*10000 = 315500000.00  kg m^2/s^2

total energy = 90590389.66 +315500000.00 = 409091242.28 kg m^2/s^2

P_o =\frac{409091242.28}{750} = 545454.99 j/s

effeciency\ n = \frac{P_o}{P} = \frac{545454.99}{1118549.81} = 0.49

effeciency n = = 49%

8 0
3 years ago
Study the interaction of the light rays with the mediums. Classify the medium in each image as being transparent or opaque.
Tresset [83]

Answer:

a) transparent

b) transparent

c) opaque

Explanation:

In the first one, the light rays go completely through, so it is transparent.

The second one I'm not too sure about. It is refraction so it's going through a different material, but the fact that it went through makes me say transparent.

Last one, the light rays are reflecting off the surface so it's opaque.

Please feel free to correct me if I'm wrong. This is just my understanding

6 0
3 years ago
Read 2 more answers
A 9.6 cm diameter circular loop of wire is in a 1.10 T magnetic field perpendicular to the plane of the loop. The loop is remove
Natali5045456 [20]

Answer:

Thus induced emf is 0.0531 V

Solution:

As per the question:

Diameter of the loop, d = 9.6\ cm = 0.096\ m

Thus the radius of the loop, R = 0.048 m

Time in which the loop is removed, t = 0.15 s

Magnetic field, B = 1.10 T

Now,

The average induced emf, e is given by Lenz Law:

e = - \frac{\Delta \phi_{B}}{\Delta t}

e = - \frac{\Delta \phi_{B}}{\Delta t}

where

\phi_{B} = magnetic flux = A\Delta B

where

A = cross sectional area

Also, we know that:

e = - \frac{A\Delta B}{\Delta t}

e = - \frac{\pi r^{2}\times (0 - 1.10)}{0.15}

e = - \frac{\pi \times 0.048^{2}\times (0 - 1.10)}{0.15}

e = 0.0531 V

The sketch is shown in the figure, where I indicates the direction of the induced current.

3 0
3 years ago
Read 2 more answers
How much time does it take for a car travelling at 5m/s in 21 metres
Paha777 [63]

Answer:

21/5 seconds or 4.2 seconds

Explanation:

Distance=Speed*Time

21=5 *Time

21/5=Time

4.2=time

7 0
3 years ago
Read 2 more answers
What is the speed of a 50 g rock if its de broglie wavelength is 3.32x10^-34m?
ivann1987 [24]
We can find the momentum of the rock by using De Broglie's relationship:
p= \frac{h}{\lambda}
where
p is the momentum
h is the Planck constant
\lambda is the De Broglie's wavelength

By using \lambda=3.32 \cdot 10^{-34} m, we find
p= \frac{6.6 \cdot 10^{-34} Js}{3.32 \cdot 10^{-34} m}=1.99 kg m/s

The momentum of the rock is
p=mv
where m=50 g=0.05 kg is the mass and v is its velocity. Rearranging the equation, we find the speed of the rock:
v= \frac{p}{m}= \frac{1.99 kg m/s}{0.05 kg}=39.8 m/s
7 0
3 years ago
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