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nlexa [21]
4 years ago
10

A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/secon

d. The softball’s velocity goes to 0 meters/second in 0.8 seconds when caught. If the softball has a mass of 0.2 kilograms, what’s the force of the impact? Use F = ma, where .
Physics
1 answer:
Pani-rosa [81]4 years ago
4 0

Answer:  The force of the impact is <u><em>8.0 Newtons</em></u>

Explanation:

Given

Initial\: velocity(V_i)= 32.0\, \frac{m}{s} ,Final\, velocity ( V_f)=0 \frac{m}{s},Time(t)=0.8 seconds

Using equation of motion

V_f=V_i+at  where a= acceleration of softball

=>0=32+a\times 0.8=>a= -40\, \frac{m}{s^{2}}

Thus magnitude of the force of the impact is

F=\left | ma \right |=>F=0.2\times 40\; Newtons=8.0\: Newtons

Thus the force of the impact is <u><em>8.0 Newtons</em></u>

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