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drek231 [11]
3 years ago
13

according to newtons second law of motion, when an object is acted on by an unbalanced force, how will that object respond?

Physics
2 answers:
Elodia [21]3 years ago
8 0

Explanation:

Newton's second law of motion states that when a certain force is acted on an object then it is equal to the mass m of that object multiplied by the acceleration a of the object.

Mathematically, the relation is as follows.

                             F = m × a

Thus, we can conclude that when an object is acted on by an unbalanced force then the object will start to accelerate.



olga_2 [115]3 years ago
6 0
When an object is acted on by an unbalanced force, then that object will accelerate.
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larisa [96]

Answer:

0.38°

Explanation:

\theta = Angle

m = Number

d = Distance

n = Refractive index of liquid = 1.25

a denotes air

l denotes liquid

In the case of double split interferance we have the relation

m\lambda=dsin\theta

For air

m\lambda_a=dsin\theta_a

For liquid

m\lambda_l=dsin\theta_l

Dividing the two equations

\frac{m\lambda_a}{m\lambda_l}=\frac{dsin\theta_a}{dsin\theta_l}\\\Rightarrow \frac{\lambda_a}{\lambda_l}=\frac{sin\theta_a}{sin\theta_l}

Wavelength ratio = n

n=\frac{sin\theta_a}{sin\theta_l}\\\Rightarrow \frac{sin0.48}{1.25}=sin\theta_l\\\Rightarrow \theta_l=sin^{-1}\frac{sin0.48}{1.25}\\\Rightarrow \theta_l=0.38^{\circ}

The angular separation is 0.38°

5 0
4 years ago
Read 2 more answers
A 2.5 kg steel gasoline tank can holds 20.0 L of gasoline when full. What is the average density (in Kg/m^3) of the full gas can
yarga [219]

Answer:

D=792.3\ kg/m^3

Explanation:

<u>Average Density </u>

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The tank can hold 20 L of gasoline when full. Converting to cubic meters

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\displaystyle V_t=\frac{2.5}{7800}=3.205\times 10^{-4}\ m^3

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The average density is

\displaystyle D=\frac{16.1}{0.0203}

\boxed{D=792.3\ kg/m^3}

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3 years ago
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Nostrana [21]

Answer:

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3 years ago
67 points plus brainlest if done correctly.I will report you if you answer 3 or less of the questions, also must post all the an
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im sorry but i dont know, good luck at finding someone else who does.

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