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blondinia [14]
3 years ago
6

Suppose that the separation between two speakers A and B is 4.80 m and the speakers are vibrating in-phase. They are playing ide

ntical 134-Hz tones and the speed of sound is 343 m/s. An observer is seated at a position directly facing speaker B in such a way that his line of sight extending to B is perpendicular to the imaginary line between A and B. What is the largest possible distance between speaker B and the observer, such that he observes destructive interference
Physics
1 answer:
Hatshy [7]3 years ago
4 0

Answer:

X=8.44m

Explanation:

From the question we are told that

Distance b/w A&B x=4.80m

Frequency f=134Hz

Sound speed v=343m/s

Generally the equation for wavelength is mathematically given as

\lambda=v/f

\lambda/2=1/2*v/f

\lambda/2=1/2*\frac{343}{135}

\lambda/2=1.27037037

Generally the destructive interference X is mathematically given by

\sqrt{4.8^2 +X^2} -X=1.27037037\\

23.04+BC^2=X^2+1.613+2.54*X

Therefore the destructive interference is

X=8.44m

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