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IrinaVladis [17]
3 years ago
12

6th grade math help me pleaseeeee

Mathematics
2 answers:
Zinaida [17]3 years ago
5 0

Answer:

49

Step-by-step explanation:

-7^2

= -7 * -7

= 49

Hope this helps!      :3

plz mark as brainliest!

beks73 [17]3 years ago
4 0

Answer: 49

Step-by-step explanation:

first, determine the sign.

7^2

then, write out as regular multiplication.

7 x 7

then simply multiply.

7 x 7 = 49

You might be interested in
Canadians who visit the United States often buy liquor and cigarettes, which are much cheaper in the United States. However, the
fenix001 [56]

Answer:

(a): Marginal pmf of x

P(0) = 0.72

P(1) = 0.28

(b): Marginal pmf of y

P(0) = 0.81

P(1) = 0.19

(c): Mean and Variance of x

E(x) = 0.28

Var(x) = 0.2016

(d): Mean and Variance of y

E(y) = 0.19

Var(y) = 0.1539

(e): The covariance and the coefficient of correlation

Cov(x,y) = 0.0468

r \approx 0.2657

Step-by-step explanation:

Given

<em>x = bottles</em>

<em>y = carton</em>

<em>See attachment for complete question</em>

<em />

Solving (a): Marginal pmf of x

This is calculated as:

P(x) = \sum\limits^{}_y\ P(x,y)

So:

P(0) = P(0,0) + P(0,1)

P(0) = 0.63 + 0.09

P(0) = 0.72

P(1) = P(1,0) + P(1,1)

P(1) = 0.18 + 0.10

P(1) = 0.28

Solving (b): Marginal pmf of y

This is calculated as:

P(y) = \sum\limits^{}_x\ P(x,y)

So:

P(0) = P(0,0) + P(1,0)

P(0) = 0.63 + 0.18

P(0) = 0.81

P(1) = P(0,1) + P(1,1)

P(1) = 0.09 + 0.10

P(1) = 0.19

Solving (c): Mean and Variance of x

Mean is calculated as:

E(x) = \sum( x * P(x))

So, we have:

E(x) = 0 * P(0)  + 1 * P(1)

E(x) = 0 * 0.72  + 1 * 0.28

E(x) = 0   + 0.28

E(x) = 0.28

Variance is calculated as:

Var(x) = E(x^2) - (E(x))^2

Calculate E(x^2)

E(x^2) = \sum( x^2 * P(x))

E(x^2) = 0^2 * 0.72 + 1^2 * 0.28

E(x^2) = 0 + 0.28

E(x^2) = 0.28

So:

Var(x) = E(x^2) - (E(x))^2

Var(x) = 0.28 - 0.28^2

Var(x) = 0.28 - 0.0784

Var(x) = 0.2016

Solving (d): Mean and Variance of y

Mean is calculated as:

E(y) = \sum(y * P(y))

So, we have:

E(y) = 0 * P(0)  + 1 * P(1)

E(y) = 0 * 0.81  + 1 * 0.19

E(y) = 0+0.19

E(y) = 0.19

Variance is calculated as:

Var(y) = E(y^2) - (E(y))^2

Calculate E(y^2)

E(y^2) = \sum(y^2 * P(y))

E(y^2) = 0^2 * 0.81 + 1^2 * 0.19

E(y^2) = 0 + 0.19

E(y^2) = 0.19

So:

Var(y) = E(y^2) - (E(y))^2

Var(y) = 0.19 - 0.19^2

Var(y) = 0.19 - 0.0361

Var(y) = 0.1539

Solving (e): The covariance and the coefficient of correlation

Covariance is calculated as:

COV(x,y) = E(xy) - E(x) * E(y)

Calculate E(xy)

E(xy) = \sum (xy * P(xy))

This gives:

E(xy) = x_0y_0 * P(0,0) + x_1y_0 * P(1,0) +x_0y_1 * P(0,1) + x_1y_1 * P(1,1)

E(xy) = 0*0 * 0.63 + 1*0 * 0.18 +0*1 * 0.09 + 1*1 * 0.1

E(xy) = 0+0+0 + 0.1

E(xy) = 0.1

So:

COV(x,y) = E(xy) - E(x) * E(y)

Cov(x,y) = 0.1 - 0.28 * 0.19

Cov(x,y) = 0.1 - 0.0532

Cov(x,y) = 0.0468

The coefficient of correlation is then calculated as:

r = \frac{Cov(x,y)}{\sqrt{Var(x) * Var(y)}}

r = \frac{0.0468}{\sqrt{0.2016 * 0.1539}}

r = \frac{0.0468}{\sqrt{0.03102624}}

r = \frac{0.0468}{0.17614266944}

r = 0.26569371378

r \approx 0.2657 --- approximated

8 0
2 years ago
Fluffy, Spot and Skampy have a combined age in dog years of 91. Spot is 14 years younger than Fluffy. Skampy is 6 years older th
WITCHER [35]

Answer: fluffy = 33yrs

Spot = 19 yrs

Skampy = 39 yrs

Step-by-step explanation:

Let fluffy = x

Spot = y

Skampy =z

x + y + z = 91 -------1

x -14 =y ------2

z = x + 6 --------3

Put eqn 2 and 3 in eqn 1

x + x - 14 + x + 6 = 91

3x = 99

x = 33

y = 33-14= 19

z = 33+6 = 39

8 0
3 years ago
A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 ​respondents,
RoseWind [281]

Answer:

The statement that​ "the margin of error was given as \pm5 percentage​ points" means that the population proportion is estimated to be with a certain level of confidence, within the interval \hat{p} \pm 0.05 ; where \hat{p}[tex] is the sample's proportion. The correct answer is C. The statement indicates that the interval [tex]0.14\pm0.05 is likely to contain the true population percentage of people that prefer chocolate pie.

Step-by-step explanation:

The margin of error for proportions is given by the following formula:

z_{\alpha /2}\times\sqrt{\frac{\hat{p}\times(1-\hat{p})}{n}}

Where:

z_{\alpha /2} is the critical value that corresponds to the confidence level; the confidence level being 1-\alpha,

\hat{p} is the sample's proportion of successes,

n is the size of the sample.

In this exercise we have that \hat{p}=0.14 and that the margin of error is 0.05.

Therefore if we replace in the formula to calculate the confidence interval we get:

\hat{p}\pm 0.05=0.14\pm0.05=(0.09, 0.19)

Which means that the true population proportion is estimated to be, with a certain confidence level, within the interval (0.09, 0.19).

7 0
3 years ago
Correct answer Gets Brainliest
Lady bird [3.3K]

Answer:

x=24

Step-by-step explanation:

bc

8 0
2 years ago
Read 2 more answers
Does anybody know this??????
aniked [119]
The correct answer is 196 or Option A.
The explanation is just as complicated as the question.
7 0
3 years ago
Read 2 more answers
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