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Rainbow [258]
3 years ago
8

Give two reasons why the flame test is sometimes invalid

Chemistry
2 answers:
Harlamova29_29 [7]3 years ago
7 0

Answer: 1.A false positive and 2.A false negative.

Explanation:

A false positive the classic example is the contamination of almost any sample with sodium ions which gives an intense yellow line even when the sodium is present as only impurity.

A false negative here sodium ions is the culprit that masks other emissions unless the emissions are resolved spectroscopically rather than simply visually.

zlopas [31]3 years ago
6 0
The two reason behind the invalidity of flame test are false positive and false negative.
while performing the flame test you must have to be accurate otherwise you will get false results may be positive for some element or may be negative in case the element is present. The main reason to get the false positive and false negative is the presence and contamination of sodium.
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In rabbits, the gene for black fur is dominant (F), but the gene for white fur
Pepsi [2]
A white rabbit would therefore have (ff)

If a trait is recessive, then it can only be expressed if both alleles (individual letters) are recessive (lowercase).
7 0
3 years ago
Consider the following precipitation reaction (balanced). precipitation reaction: 2NH4Br(aq)+Pb(C2H3O2)2(aq)⟶2NH4C2H3O2(aq)+PbBr
sweet [91]

Answer:

Pb2+ (aq) & 2Br- (aq) --> PbBr2 (s).

Explanation:

Equation of the reaction:

Pb(C2H32O2)2 (aq) + 2 NH4Br (aq) --> 2NH4C2H3O2 (aq) + PbBr2 (s)

Ionic equation:

Pb+2(aq) + 2(C2H3O2)-1 (aq) + 2(NH4+) (aq) + 2Br-1 (aq) --> 2(NH4+) (aq) + 2(C2H3O2-) (aq) + PbBr2 (s)

2(NH4)+1(aq) & 2(C2H3O2)-1 (aq) cancel out from both sides, you are left with the net ionic equation :

Pb2+ (aq) & 2Br- (aq) --> PbBr2 (s).

6 0
3 years ago
Which is a property of an ideal gas?
AlekseyPX
HEY THERE!

THE ANSWER IS: the properties of an ideal gas are: An ideal gas consists of a large number of identical molecules. The volume occupied by the molecules themselves is negligible compared to the volume occupied by the gas. The molecules obey Newton's laws of motion, and they move in random motion.

CREDITS:
<span>physics.bu.edu/~duffy/py105/Idealgas.htm</span>
6 0
4 years ago
Read 2 more answers
How many grams of Chromium(III) nitrate are produced when Chromium reacts with 0.85 moles of Lead(IV) nitrate to produce chromiu
mina [271]

Grams of Chromium(III) nitrate produced : 268.95 g

<h3>Further explanation</h3>

Given

0.85 moles of Lead(IV) nitrate

Required

grams of Chromium(III) nitrate

Solution

Reaction

Balanced equation :

<em>2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb </em>

From the equation, mol ratio of Pb(NO₃)₄  : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃

mol Cr(NO₃)₃ =

\tt \dfrac{4}{3}\times 0.85=1.13

Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :

mass = mol x MW

mass = 1.13 x 238.0108

mass = 268.95 g

7 0
3 years ago
A solution is prepared by combining 5.00 mL of 4.8x10-4 M NaSCN solution, 2.00 mL of 0.21 M Fe(NO3)3 solution and 13.00 mL of 0.
Tcecarenko [31]

Answer:

The analytical concentrations of thiocyanate ions:

[SCN^-]=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=0.063 mol/L

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

1) Moles of sodium thiocyanate  = n

Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L

(1 mL = 0.001L)

Molarity of the sodium thiocyanate = 4.8\times 10^{-4} M

n=4.8\times 10^{-4} M\times 0.005 L=2.4\times 10^{-6}mol

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.

So, moles of thioscyanate ions in 2.4\times 10^{-6}mol  of NaSCN.

=1\times 2.4\times 10^{-6}mol=2.4\times 10^{-6}mol

2) Moles of ferric nitrate = n'

Volume of ferric nitrate solution = 2.00 mL = 0.002 L

Molarity of the ferric nitrate = 0.21 M

n'=0.002 M\times 0.21 L=0.00042 mol

1 mole of ferric nitrate has 3 moles of ferric ions.

So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

3\times 0.00042 mol=0.00126 mol

Volume of nitric acid = 13.00 mL

Total volume by adding all three volumes of solutions = V

V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L

The analytical concentrations of thiocyanate ions:

[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L

3 0
3 years ago
Read 2 more answers
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