Hydrogen peroxide is a powerful oxidizer. When exposed to sunlight it quickly decomposes to form water and oxygen as given by the following equation.
2H2O2(aq) → 2H2O(l) + O2(g)
Hydrogen peroxide is commercially available as a 30% w/w solution, which is the concentration that would facilitate the above reaction. This implies that the concentration would be 30 g of H2O2 in 100 g of the solution.
Answer:
Keep it simple. If all the oxygen contained in the 200 grams of potassium chlorate is produced in the decomposition, then all we have to do is find out how many grams of oxygen are there in the 200 grams. This we can do by calculating the ratio of oxygen mass to the whole. Using 39.1 for potassium, 35.45 for chlorine and 3 times 16, or 48 for the oxygen, we get a total of 122.55 grams per mole for potassium chlorate, of which 48 grams are oxygen. This ratio is 48/122.55. This ratio times the original 200 grams of the compound, gives us 78.34 grams of oxygen produced.
Explanation:
It would be in the fourth shell.
