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Lera25 [3.4K]
3 years ago
12

A group of students want to see how temperature affects the time spilled water to dry up what will be independent and dependent

variable
Chemistry
1 answer:
erastova [34]3 years ago
4 0
Independent is the temperature dependent is the time
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What is the temperature of 0.5 moles of water vapor that occupies 120 dm3 and applies a pressure of 15,000 Pa to its container?
AleksandrR [38]

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The answer is C. 7.52 K

Explanation:

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Consider the reaction:
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2 one is the correct one

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2 years ago
Calculate the energy in joules and calories required to heat 25.0 g of water from 12.5C to 25.7C
Alex Ar [27]
The heat (Q) required to raise the temp of a substance is:<span>Q=m∗Cp∗ΔT</span><span> where m is the mass of the object (25.0g in this case), Cp is the specific heat capacity of the substance (for water Cp = 1.00cal/gC, or 4.18J/gC,
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What was George Washington Caver professional information ​
Sedbober [7]

Explanation:

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5 0
3 years ago
Read 2 more answers
What is the entropy change for the freezing process of 1 mole of liquid methanol at its freezing temperature (–97.6˚C) and 1 atm
Rudiy27

Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K

Explanation :

Formula used :

\Delta S=\frac{\Delta H_{freezing}}{T_f}

where,

\Delta S = change in entropy

\Delta H_{fus} = change in enthalpy of fusion = 3.17 kJ/mol

As we know that:

\Delta H_{fus}=-\Delta H_{freezing}=-3.17kJ/mol=-3170J/mol

T_f = freezing point temperature = -97.6^oC=273+(-97.6)=175.4K

Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{freezing}}{T_m}

\Delta S=\frac{-3170J/mol}{175.4K}

\Delta S=-18.07J/mol.K

Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K

4 0
3 years ago
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