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ella [17]
3 years ago
12

What is the length of side BC if AC is 5 square root 2 m?

Mathematics
1 answer:
Jet001 [13]3 years ago
4 0
This is a right triangle, so AC is a hypotenuse. The other angles are each 45 degrees, so the legs AB and BC are equal length. a^2 + b^2 = c^2 a = b 2a^2 = (5sqrt2)^2 = 50 a^2 = 25 a = 5 Answer: 5
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45 liters of helium at $.42 per liter
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Answer:

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Select the correct answer from each drop-down menu.
ella [17]

Answer:

A non-equilateral rhombus.

Step-by-step explanation:

We can solve this graphically.

We start with square:

ABCD

with:

A = (11, - 7)

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C = (11, - 1)

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Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:

AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13

BC =  √( (11 - 9)^2 + (-1 -(-4))^2) = √13

CD =  √( (11 - 13)^2 + (-1 -(-4))^2)  = √13

DA =  √( (11 - 13)^2 + (-7 -(-4))^2) = √13

And we change C by C' = (11, 1)

In the image you can see the 5 points and the figure that they make:

The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.

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10! If you use the trapezoid area formula and plug in the known values, just solve for h(height)
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