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Mrac [35]
3 years ago
9

What is the maximum height the bee reaches as it flies from A to B?

Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0
It's asking you to find the derivative, which is -0.06x+1.8, and then, when it equals zero, it has reached the top. that is, -0.06x+1.8=0, or x= 30. plug that into the original formula, and you get -0.03(30)²+1.8(30)-24, or 3. the answer is 3 (inches, presumably)
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(12 divided by 3) 2 – (18 divided by 3 2)) < (4 divided by 2)
gladu [14]

Answer:

(12 \div 3)(2 - (18 \div 32) \\  = 4(2 -  \frac{19}{16} ) \\  = 4( \frac{23}{16} ) \\  =  \frac{23}{4}  \\ since \: (4 \div 2) = 2 \\  \frac{23}{4} is \: not \:  < 2 \: but \: its \:  > 2

4 0
3 years ago
Need help for 3 2/3 - 1/2
const2013 [10]
3 2/3 - 1/2
= 11/3 - 1/2
= 22/6 - 3/6
= 19/6
= 3.1666666667
3 0
3 years ago
Read 2 more answers
If the instructions for a problem ask you to use the smallest possible domain to completely graph two periods of y = 5 + 3 cos 2
Finger [1]
The period of a sinusoid \cos 2(x-c) is \dfrac{2\pi}2=\pi, so any range such that \mathrm{Xmax}-\mathrm{Xmin}=2\pi will give two complete periods.
5 0
3 years ago
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A listing of observed values and the corresponding frequency of occurrence of each value is called a
atroni [7]

Answer: frequency

Step-by-step explanation:

3 0
3 years ago
Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x
Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = 3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4

fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

x(x^{2}+x) \neq 0

If x = 0, the function doesn't exist.

x^{2}+x \neq0

x(x+1) \neq0

x+1\neq0

x\neq-1

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

5 0
3 years ago
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