Which type of reaction has the highest penetration ability? Alpha Beta Gamma Nuclear

A certain object has a volume of 25.0 ml and a mass of 100 g. what is the density of the object

Tpy6a [65]

Density= mass/volume

= 100/25
density = 4g/ml

8 0

3 years ago

What is the conversion factor for in^3 to cm^3

DochEvi [55]

You multiply by 16.3871

5 0

3 years ago

What amount of carbon dioxide (in moles) is produced from the reaction of 2.24 moles of ethanol with excess oxygen?

algol13

Answer : The amount of carbon dioxide produced is, 197.12 grams.

Explanation : Given,

Moles of ethanol = 2.24 mole

Molar mass of carbon dioxide = 44 g/mole

The balanced chemical reaction will be,

$C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O$

First we have to calculate the moles carbon dioxide.

From the balanced chemical reaction, we conclude that

As, 1 mole of ethanol react to give 2 moles of carbon dioxide

So, 2.24 mole of ethanol react to give $2\times 2.24=4.48$ moles of carbon dioxide

Now we have to calculate the mass of carbon dioxide.

$\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2$

$\text{Mass of }CO_2=4.48mole\times 44g/mole=197.12g$

Therefore, the amount of carbon dioxide produced is 197.12 grams.

8 0

3 years ago

Burning of paper is chemical change why? write with reaction.

Jet001 [13]

Answer:

Burning of paper is not a physical change.It is chemical change as ash is formed in the process which is new compound and oxides of carbon are also released during the process!

4 0

3 years ago

An analytical chemist weighs out 0.093g of an unknown monoprotic acid into a 250mL volumetric flask and dilutes to the mark with

Kamila [148]

Answer:

The molar mass of the unknown acid is 89 g/mol

Explanation:

Step 1: The balanced equation

HA(aq) + NaOH(aq) → NaA(aq) + H2O(l)

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

Step 2: Data given

Mass of the acid = 0.093 grams

volume = 250 mL

titrates with 0.16 M NaOH

adds 6.5 mL NaOH

Step 3: Calculate moles of NaOH

We know the concentration and volume of NaOH needed to neutralize the acid.

By determining the moles of NaOH in that volume in liters (95.9mL=0.0959L), the moles of acid in the original sample can be determined from the reaction stoichiometry.

Moles = Molarity * Volume

Moles = 0.16 M * 0.0065 L

Moles = 0.00104 moles NaOH

Step 4: Calculate moles of the unknown acid:

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

For 0.00104 moles NaOH we have 0.00104 moles of HA

Step 5: Calculate the molar mass of the acid

Molar mass Ha = Mass Ha / moles Ha

Molar mass Ha = 0.093 grams / 0.00104 moles

Molar mass Ha = 89.42 g/mol ≈89 g/mol

The molar mass of the unknown acid is 89 g/mol

3 0

3 years ago