Answer: The new concentration of a solution of is 0.2 M 10.0 mL of a 2.0 M
solution is diluted to 100 mL.
Explanation:
Given: = 10.0 mL,
= 2.0 M
= 100 mL,
= ?
Formula used to calculate the new concentration is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the new concentration of a solution of is 0.2 M 10.0 mL of a 2.0 M
solution is diluted to 100 mL.
Answer:
0,508g of H₂O₂
Explanation:
For the reaction:
2KMnO₄(aq) + H₂O₂(aq) + 3H₂SO₄(aq) → 3O₂(g) + 2MnSO₄(aq) + K₂SO₄(aq) + 4H₂O(l)
2 moles of KMnO₄ react with 1 mol of H₂O₂.
In the titration, moles of KMnO₄ required were:
1,68M×0,0178L = 0,0299 moles of KMnO₄. Moles of H₂O₂ are:
0,0299 moles of KMnO₄× = 0,01495 moles of H₂O₂. As molar mass of H₂O₂ is 34,01g/mol, mass of H₂O₂ was dissolved is:
0,01495 moles of H₂O₂× = <em>0,508g of H₂O₂</em>