Answer:
a.the length of midsegment of an equilateral triangle with side lengths of 12.5 cm.=12.5/2=6.25cm
b.
sinceUT is the perpendicular bisector of line segment AB, where T is on AB, find the length of AT given AT = 3x + 6 and TB = 42 - x.
than AT=BT
3x+6=42-x
3x+x=42-6
x=36/4=9
AT=3×9+6=27+6=33
c.
since angle EFG has angle bisector FH, where EF = GF, find the value of y if EH = 5y + 10 and HG = 28 - y.
EH=GH
5y+10=28-y
6y=28-10
y=18/6=3
0.1875 you must divide 3 by 16 the numerator by the denominator
For this case we have the following function:
f (x) = (1/3) * (4 ^ x)
We must evaluate the function for x = 2
We have then:
f (2) = (1/3) * (4 ^ 2)
Rewriting:
f (2) = (1/3) * (16)
f (2) = 16/3
Answer:
The function evaluated at x = 2 is:
f (2) = 16/3
option A
Answer:
A
Step-by-step explanation:
All pieces of data for seventh grade classes are larger than that of any kindergarten class on the table. This also proves with the mean provided.
The MAD, mean absolute deviation, helps you to identify the variation. The MAD for seventh grade was significantly larger than that of the kinder classes. The range for both sets of data is two times one another, further proving that 7th grade classes varies more.
C and D are irrelevant, and B says "varies less" which is the opposite of what's going on.
Hope that helps!
3/4 + 1/12 = 10/12 and then you simplify it and get 5/6 as your final answer.
