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Radda [10]
3 years ago
6

A boy pushes forward a cart of groceries with a total mass of 40.0 kg. What is the acceleration of the cart if the net force on

the cart is 60.0 N?
Physics
1 answer:
melisa1 [442]3 years ago
6 0

1.5m/s2

F=ma

a=F/m

a=60/40

a=1.5m/s2

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Two planets, Dean and Sam, orbit the Sun. They each have with circular orbits, but orbit at different distances from the Sun. De
lyudmila [28]

Answer:

The correct answer is Dean has a period greater than San

Explanation:

Kepler's third law is an application of Newton's second law where the force is the universal force of attraction for circular orbits, where it is obtained.

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When applying this equation to our case, the planet with a greater orbit must have a greater period.

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The correct answer is Dean has a period greater than San

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Investigators are most likely to use the case history method when they study
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Investigators are most likely to use the case history method when they study <span>a rare behavior or an unusual person.
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Read this article discussing the amount of time that people of various ages and education levels report spending on different te
iVinArrow [24]

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<h3>What is a survey?</h3>

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7 0
2 years ago
A circular coil of radius r = 5 cm and resistance R = 0.2 is placed in a uniform magnetic field perpendicular to the plane of th
Yuri [45]

Answer:

the question is incomplete, the complete question is

"A circular coil of radius r = 5 cm and resistance R = 0.2 ? is placed in a uniform magnetic field perpendicular to the plane of the coil. The magnitude of the field changes with time according to B = 0.5 e^-t T. What is the magnitude of the current induced in the coil at the time t = 2 s?"

2.6mA

Explanation:

we need to determine the emf induced in the coil and y applying ohm's law we determine the current induced.

using the formula be low,

E=-\frac{d}{dt}(BACOS\alpha )\\

where B is the magnitude of the field and A is the area of the circular coil.

First, let determine the area using \pi r^{2} \\ where r is the radius of 5cm or 0.05m

A=\pi *(0.05)^{2}\\ A=0.00785m^{2}\\

since we no that the angle is at 0^{0}

we determine the magnitude of the magnetic filed

B=0.5e^{-t} \\t=2s

E=-(0.5e^{-2} * 0.00785)

E=-0.000532v\\

the Magnitude of the voltage is 0.000532V

Next we determine the current using ohm's law

V=IR\\R=0.2\\I=\frac{0.000532}{0.2} \\I=0.0026A

I=2.6mA

6 0
4 years ago
Which chemical equation is balanced?
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Answer:

<h3>C no.</h3>

Explanation:

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6 0
3 years ago
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