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Volgvan
3 years ago
9

A bike tire has a diameter of 14 inches. It runs over a piece of gum that sticks to the tire. Write a cosine function that descr

ibes the height of the gum above the ground as a function of angular distance.
a. y = -7 cos x + 7


b. y = 7 cos x + 14


c. y = -7 cos x + 14


d. y = 14 cos x + 28

Mathematics
1 answer:
Rina8888 [55]3 years ago
6 0

Answer:

  a.  y = -7cos(x) +7

Step-by-step explanation:

The middle level of the gum is 7 inches above the ground, and it oscillates 7 inches either side of that. Thus the offset of the cosine function (average height) is 7 and the multiplier (amplitude of oscillation) is also 7. The -7 on the cosine multiplier means the height of the gum is zero at x=0.

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Work the following area application problem.
Nookie1986 [14]

SInce you need 1.5 feet of overhang, add 3 feet to each axis dimension 1.5 on each side):

Minor Axis = 18 + 3 = 21 feet

Major axis = 25 + 3 = 28 feet


The area of an ellipse is found by multiplying half the minor axis by half the major axis by PI.


1/2 minor axis = 21 / 2 = 10.5

1/2 major axis = 28 / 2 = 14

Using 3.14 for PI

Area = 10.5 x 14 x 3.14 = 147 x 3.14 = 461.6 sq ft

7 0
3 years ago
Read 2 more answers
What is the percent of 840 is 546
lesantik [10]
K so its an equation      546         x
                                   over   = over
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when u do cross multiplication it will be 840x=546 * 100
                                                       x is about 64%
Hope this is helpful
4 0
3 years ago
Picture, brainliest
seraphim [82]

Answer:

165

Step-by-step explanation:

210/3=70

110/2=55

70×11=770

55*11=605

770-605= 165

y would be 165 greater in the table than on the graph when x=11

7 0
3 years ago
Consider the spiral given by c(t) = (e2t cos(2t), e2t sin(2t)). Show that the angle between c and c' is constant. c'(t) = _____L
Tcecarenko [31]

Answer:

angle is 45° which is constant

Step-by-step explanation:

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<u>Please see the attached file</u>

8 0
3 years ago
I can't figure this out
andriy [413]
Suppose that equation of parabola is
y =ax² + bx + c


Since parabola passes through the point (2,−15) then 
−15 = 4a + 2b + c

Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c

Since parabola passes through the point (−3,−5), then 
−5 = 9a − 3b + c


Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5

Solving it we get that 
a = −2, b = −4, c = 1

Thus, equation of parabola is
y = −2x²− 4x + 1

____________________

Rewriting in the form of 
(x - h)² = 4p(y - k)

i) -2x² - 4x + 1 = y

ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)

iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)

iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)

v) -3(x + 7/6)² = y - 445/36 

vi) (x + 7/6)² = -⅓(y - 445/36) 
(Shifting -⅓ to RHS)

vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p) 


So, after rewriting the equation would be - 

(x + 7/6)² = 4(-⅛)(y - 445/36)

__________________

I hope this is what you wanted.

Regards,
Divyanka♪
__________________
6 0
3 years ago
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