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enyata [817]
3 years ago
11

More 6th grade science! :((

Chemistry
1 answer:
Rus_ich [418]3 years ago
7 0

Answer:

B- celebrated

Explanation:

It was a party, parties are celebrated.

This definitely isn't science but...

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What is the molarity of the two solutions <br> 0.150 mol of NaOH in 1.80 L of solution
padilas [110]
1 mole of MgS = 24.3 + 32.1 = 56.4 g

35.1 g MgS x 1 mol / 56.4 g = 0.622 mol

M = 0.622 mol / 0.835 L = 0.745 mol/L
4 0
4 years ago
Im just gonna keep spamming this question lmmaaooo<br> anyone else got inssttaaa?
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Yeeet wanna be mootss???

6 0
3 years ago
Calculate the ionization energy, ????????, of the one‑electron ion Be3+. The electron starts in the lowest energy level, ????=1.
spin [16.1K]

Answer:

3.49X10⁻¹⁷ J

Explanation:

The energy of an electron is given by the equation:

E = - (2.18x10^{-18})Z^2(\frac{1}{n^2})

Where Z is the number of protons of the atom and n is the energy level of the electron. For Be, Z = 4.

When n tends to infinity (1/n²) tends to 0, and at this point, the electron has left the atom, so it has ionized.

The ionization energy then is the energy of the electron that left the atom less the energy of the electron in the energy level:

I.E = - (2.18x10⁻¹⁸)x4²x0 - (-(2.18x10⁻¹⁸)x4²x(1/1²))

I.E = 3.49X10⁻¹⁷ J

3 0
3 years ago
If an acid has a ka=1.6x10^-10, what is the acidity of the solution?
LUCKY_DIMON [66]
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
 In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+.  If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
5 0
3 years ago
Help me answer this question for points!
labwork [276]

Answer:

I am pretty sure Danny Duncan told me 69

Explanation:

niice

6 0
3 years ago
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