What conclusion can be made about the solubility of nickel (II)

Taxol is a potent chemotherapeutic agent (isolated from the Pacific Yew tree) which is especially effective against ovarian canc

butalik [34]

Answer:

Amine

Explanation:

The functional groups contained in Taxol are :

Ketone , Ester, Amide and Alcohol

while the functional group that is not contained in the Taxol is Amine

Taxol is a very potent anti-cancer chemotherapeutic, and it is also groped into a class called Taxanes and this makes it effective in the treatment of breast and ovarian cancer.

8 0

2 years ago

Briefly explain why the bulk temperature of the water remains low (at room temperature)

elena55 [62]

If the humidity of the room is low, the water that contacts the air directly could evaporate and takes some energy from the bulk thus decreasing its temperature steadily. This allows the water to have a lower temperature.

4 0

2 years ago

Provide an appropriate alkyne starting material A and intermediate product B. Omit byproducts. The number of carbon atoms in the

nadezda [96]

Answer:

C4H6 + 2HBr = C4H8Br2

Explanation:

Alkynes are organic molecules made of the functional group carbon-carbon triple bonds and are written in the empirical formula of CnH2n−2. They are unsaturated hydrocarbons.

Furthermore, Halogenation reaction of any alkyne such as but-2-yne with any of the hydro halogenated compounds such as HBr, HCl, HF or HI will give an alkane that will have the same number of carbon atoms in the starting material and in the final product.

Halogenation reaction is a reaction that occurs when one or more halogens are added to a substance. Halogens is the seventh column in the periodic table and it include fluorine, chlorine, bromine, iodine, and astatine.

6 0

2 years ago

Use the Henderson-Hasselbalch equation, eq. (3), to calculate the pH expected for a buffer solution prepared from this acid and

notka56 [123]

Answer:

$pH=4.56$

Explanation:

Hello there!

In this case, given the Henderson-Hasselbach equation, it is possible for us to compute the pH by firstly computing the concentration of the acid and the conjugate base; for this purpose we assume that the volume of the total solution is 0.025 L and the molar mass of the sodium base is 234 - 1 + 23 = 256 g/mol as one H is replaced by the Na:

$n_{acid}=\frac{0.2g}{234g/mol}=0.000855mol\\\\n_{base}= \frac{0.2g}{256g/mol}=0.000781mol$