Answer: D) It has two more electrons than protons.
Explanation: Sulphur (S) is an element with atomic number 16 and thus contains 16 electrons. A neutral atom contains equal number of protons and electrons.
![S:16:[Ne]3s^23p^4](https://tex.z-dn.net/?f=S%3A16%3A%5BNe%5D3s%5E23p%5E4)
An atom on losing electrons gains positive charge and on gaining electrons gain negative charge.
Sulphide ion 
is formed by gaining 2 electrons to attain stable configuration of argon and thus contains two more electrons than protons.
![S^{2-}:18:[Ne]3s^23p^6:[Ar]](https://tex.z-dn.net/?f=S%5E%7B2-%7D%3A18%3A%5BNe%5D3s%5E23p%5E6%3A%5BAr%5D)
Answer:
CH₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 1 g
Mass of CO₂ = 3.14 g
Mass of H₂O = 1.29 g
Empirical formula =?
Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:
For Carbon, C:
Mass of CO₂ = 3.14 g
Molar mass of CO₂ = 12 + (2×16)
= 12 + 32
= 44 g/mol
Molar mass of C = 12 g/mol
Mass of C =?
Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂
Mass of C = 12/44 × 3.14
Mass of C = 0.86 g
For hydrogen, H:
Mass of C = 0.86 g
Mass of compound = 1 g
Mass of H =?
Mass of H = (Mass of compound) – (mass of C)
Mass of H = 1 – 0.86
Mass of H = 0.14 g
Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:
Mass of C = 0.86 g
Mass of H = 0.14 g
Divide by their molar mass
C = 0.86 / 12 = 0.07
H = 0.14 / 1 = 0.14
Divide by the smallest
C = 0.07 / 0.07 = 1
H = 0.14 / 0.07 = 2
Thus, the empirical formula of cyclopropane is CH₂
First you need to know Avogadro's number which is 6.02 times 10^23 molecules in 1 mole of a substance. So now just divide your number by Avagadro's number to get the number of moles.
This is actually incorrect, the distance as stated above either from trough to trough or from crest to crest within a corresponding wave, would be referred or called as the wavelength of the given wave.
