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3 years ago

The model below shows an atom of an element. What is the atomic number of this atom? 6 8 9 16

Chemistry

2 answers:

ss7ja [257]3 years ago

7 0

this is the picture diagram. and the answer is B) 8

barxatty [35]3 years ago

6 0

A picture would be nice

The question asks that theres a model down below can you add the picture just go to the bottom of your question is should say Edit press that and it should let you edit and then add the picture

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Why is sulphur more reactive than chlorine

Marina86 [1]

Answer:

Because the most reactive elements are<em> HALOGENS</em>.

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3 years ago

Read 2 more answers

Name the following compound: KI

lbvjy [14]

Explanation:

--KI:Potassium iodide

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3 years ago

What charge would you expect for an formed by Ca?

Tema [17]

Answer:

What is the charge of CA?

Table of Common Element Charges

Number Element Charge

17 chlorine 1-

18 argon 0

19 potassium 1+

20 calcium 2+

88 more rows•Dec 24, 2018

6 0

3 years ago

If the heat of fusion for water is 334 j/g, how many Jules are needed to melt 45.0 g of ice at 0.0°c?

finlep [7]

Given parameters:

Heat of fusion of water = 334j/g

Mass of ice = 45g

Temperature of ice = 0.0°c

Unknown:

Amount of heat needed to melt = ?

Solution:

This is simply a phase change and a latent heat is required in this process.

To solve this problem; use the mathematical expression below;

H = mL

where m is the mass

L is the heat of fusion of water;

H = 45 x 334 = 15030J

7 0

4 years ago

Plz help, I will give brainliest.

baherus [9]

Answer: The value of $K_c$ is 2

Explanation:

Moles of $N_2O_4$ = 1.0 mole

Volume of solution = 1.00 L

Initial concentration of $N_2O_4$ = $\frac{1.0mol}{1.00L}=1.0M$

Equilibrium concentration of $NO_2$ = $\frac{1.0mol}{1.00L}=1.0M$

The given balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initial conc. 1.0 M 0 M

At eqm. conc. (1.0-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

Given : 2x = 1.0

x= 0.5

Now put all the given values in this expression, we get :

$K_c=\frac{(1.0)^2}{(1.0-0.5)}$

$K_c=2$

Thus the value of $K_c$ is 2

4 0

3 years ago