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3 years ago

Why is hydrogen (H) placed with the elements in Group 1A?

Chemistry

2 answers:

Alex787 [66]3 years ago

6 0

It has ns1 electron configuration like the alkali metals.

NISA [10]3 years ago

6 0

The answer is -

It has the same number of valence electrons

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A pure compound is composed of? pls Answer this directly

brilliants [131]

A pure chemical compound is a chemical substance that is composed of a particular set of molecules or ions that are chemically bonded.

7 0

2 years ago

Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 13. g of butane is m

12345 [234]

Answer: The maximum amount of water that could be produced by the chemical reaction is 20.16 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For butane:

Given mass of butane = 13 g

Molar mass of butane = 58.12 g/mol

Putting values in equation 1, we get:

$\text{Moles of butane}=\frac{13g}{58.12g/mol}=0.224mol$

For oxygen gas:

Given mass of oxygen gas = 70.9 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{70.9g}{32g/mol}=2.216mol$

The chemical equation for the reaction of butane and oxygen gas follows:

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

By Stoichiometry of the reaction:

2 moles of butane reacts with 13 moles of oxygen gas

So, 0.224 moles of butane will react with = $\frac{13}{2}\times 0.224=1.456mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water

So, 0.224 moles of butane will produce = $\frac{10}{2}\times 0.224=1.12moles$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.12 moles

Putting values in equation 1, we get:

$1.12mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.12mol\times 18g/mol)=20.16g$

Hence, the maximum amount of water that could be produced by the chemical reaction is 20.16 grams

8 0

3 years ago

Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise

USPshnik [31]

Answer:

t = 37.1 s

Explanation:

The equation for the reaction is given as;

2 N2O5(g) --> 4 NO2 + O2

Initial: 0.110 - -

change: -2x +4x +x

Final: 0.110 - 2x +4x +x

But final = 0.150atm;

0.110 - 2x + 4x + x = 0.150 atm

3x = 0.150 - 0.110

x = 0.0133 atm

Pressure in reactant side;

0.110 - 2x

0.110 - 2 (0.0133) = 0.0834 atm

The integral rate law expression is given as;

ln ( [A] / [Ao] ) = -kt

k = rate constant = 7.48*10^-3*s-1

ln (0.0834/0.11) = (7.48*10^-3) t

upon solving, t = 37.1 s

3 0

3 years ago

Mica peels apart in parallel sheets because the chemical bonds between sheets are weak and the chemical bonds within sheets are

Makovka662 [10]

The answer is supposed to be true

7 0

3 years ago

What volume of O2 is required to react with CS2 to produce 4 liters of CO2?

Alenkasestr [34]

Answer:

12 L of O₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CS₂ + 3O₂ —> CO₂ + 2SO₂

From the balanced equation above,

3 L of O₂ reacted to produce 1 L of CO₂.

Finally, we shall determine the volume of O₂ required to produce 4 L of CO₂. This can be obtained as follow:

From the balanced equation above,

3 L of O₂ reacted to produce 1 L of CO₂.

Therefore, xL of O₂ will react to produce 4 L of CO₂ i.e

xL of O₂ = 3 × 4

xL of O₂ = 12 L

Thus, 12 L of O₂ is needed for the reaction.

3 0

3 years ago