Question

If the heat of fusion for water is 334 j/g, how many Jules are needed to melt 45.0 g of ice at 0.0°c?

Answer 1

Given parameters:

Heat of fusion of water  = 334j/g

Mass of ice  = 45g

Temperature of ice =  0.0°c

Unknown:

Amount of heat needed to melt = ?

Solution:

This is simply a phase change and a latent heat is required in this process.

  To solve this problem; use the mathematical expression below;

             H  = mL

where m is the mass

            L is the heat of fusion of water;

              H  = 45 x 334  = 15030J