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2 years ago

What elements does lithium resemble (in terms of electrons) when it loses 1 electron?

Chemistry

1 answer:

tigry1 [53]2 years ago

5 0

Answer:

Li atoms readily give up one electron to form positively charged, Li+ ions. These ions have the same stable electron configuration as the noble gas helium. All Group 1 atoms can lose one electron to form positively charged ions.

Explanation:

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23.It is possible to dilute a solution by...Select one:a. adding more solute to the solution.b. adding more solvent to the solut

joja [24]

To dilute a solute in a solution, it is necessary to add a proper solvent for the reaction to occur, and adding more solvent will cause the solution to dilute even more, therefore the best answer will be letter B

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1 year ago

Which of the following describes the location and energy of all the valence electrons

Nastasia [14]

Answer:

1s22s22p6<u>3s23p4</u>

Explanation:

Sulfur is located in the p block and has 6 valence electrons (the 2 exponent on the 3s and the 4 exponent on the 3p add up to 6)

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2 years ago

at a given tempature gas with a pressure of 150 kpa has volume of 0.8 l if the pressure decreases to 75kpa and the temperature r

vova2212 [387]

<span>P*V/T=constant
so P*V= constant*T
if T doesn't change then
P*V= constant
so 150kPa*0.8L=75kPa*xL
xL=150kPa*0.8L/75kPa=1.6L
hope it help</span>

8 0

3 years ago

Acids or bases can be tested by chemical_________

DedPeter [7]

Answer:

acids or bases can be tested

by chemical indicators

7 0

2 years ago

Read 2 more answers

Hurry PLEASE HELP!

avanturin [10]

B. 11,540

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually radioactive elements have an unstable atomic nucleus.

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

Nt=25 g

No=100 g

t1/2=5770 years

$\tt 25=100\dfrac{1}{2}^{T/5770}\\\\\dfrac{1}{4}=\dfrac{1}{2}^{T/5770}\\\\2=T/5770\rightarrowT=11540~years$

7 0

3 years ago