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Debora [2.8K]
2 years ago
13

HELPP ME PLEASE!! What would be the density of a 40 g object that displaces 10 ml of water?

Chemistry
1 answer:
Snezhnost [94]2 years ago
5 0

Answer:

<h2>The answer is 4.0 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 40 g

volume = 10 mL

The density of the object is

density =  \frac{40}{10}  = 4 \\

We have the final answer as

<h3>4.0 g/mL</h3>

Hope this helps you

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Greeley [361]

Electron.............

4 0
3 years ago
Hi, someone knows how to balance the following equation, and if you can thank you if you can explain how that is done:
kari74 [83]
To begin with, the equation given is not correct.
Correct equation is : CaCO3 + HCl ---> CaCl2 + H2O + CO2
It's CaCl2 not CaCl because Ca has a valency of 2 

    LHS                          RHS
CaCO3 + HCl ---> CaCl2 + H2O + CO2
First of all, to balance the equation you must look at the number of atoms on each side of the equation. 
we have 2 H on the RHS and 1 H on the LHS. So, we put a 2 on the LHS

CaCO3 + 2HCl ---> CaCl2 + H2O + CO2
Check for the LHS: 1 Ca, 1 C, 3 O, 2 H & 2 Cl on the LHS
Now check for the RHS: 1 Ca, 2 Cl, 2 H, 1 C & 3 O

Hope it helped!
7 0
3 years ago
A gaseous mixture of O2 and N2 contains 37.8% nitrogen by mass. What is the partial pressure of oxygen in the mixture if the tot
kondor19780726 [428]

Answer: The partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg

Explanation:

mass of nitrogen = 37.8 g

mass of oxygen = (100-37.8) g = 62.2 g

Using the equation given by Raoult's law, we get:

p_A=\chi_A\times P_T

p_{O_2} = partial pressure of O_2 = ?

\chi_{O_2} = mole fraction of O_2=\frac{\text{Moles of }O_2}{\text{Total moles}}

P_{T} = total pressure of mixture  = 525 mmHg

{\text{Moles of }O_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{62.2g}{32g/mol}=1.94moles

{\text{Moles of }N_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{37.8g}{28g/mol}=1.35moles

Total moles = 1.94 + 1.35 = 3.29 moles

\chi_{O_2}=\frac{1.94}{3.29}=0.59

p_{O_2}=\chi_{O_2}\times P_T=0.59\times 525=310mmHg

Thus the partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg

7 0
3 years ago
The Heliocentric model is when the sun, planets, and stars are orbiting a stationary Earth.
Anarel [89]
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3 0
2 years ago
How many hydrogen atoms are in 89.5 g of<br> C6H6 ?<br> Answer in units of atoms.
Elodia [21]

Solution :

Molar mass of C_6H_6 is :

M = 6×12 + 6×1 g

M = 78 g

78 gram of C_6H_6 contains 6.022 \times 10^{23} molecules.

So, 89.5 gram of C_6H_6 contains :

n = 6.022 \times 10^{23} \times \dfrac{89.5}{78}\\\\n = 6.91 \times 10^{23}

Now, from the formula we can see that one molecule of C_6H_6 contains 2 hydrogen atom . So, number of hydrogen atom are :

h = 2\times 6.91 \times 10^{23}\\\\h = 1.38 \times 10^{22}\ atoms

Hence, this is the required solution.

8 0
2 years ago
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