Plz help timed test I’ll give extra points

What is the difference of the polynomials?<br><br>(8r6s3 – 9r5s4 + 3r4s5) – (2r4s5 – 5r3s6 – 4r5s4)

nignag [31]

(Distribute the minus sign of the subtrahend in each term.)
= 8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵ – 2r⁴s⁵ + 5r³s⁶ + 4r⁵s⁴
(Add or subtract like terms.)
= 8r⁶s³ – 5r⁵s⁴ + r⁴s⁵ + 5r³s⁶
(If you want to factor out, then...)
= r³s³ (8r³ – 5r²s + rs² + 5s³)

6 0

3 years ago

Read 2 more answers

Please help!!!!<br><br>what is the least common denominator of 1/6, 10/11, 5/12?<br>

Vesna [10]

<h3>Answer: LCM = 132</h3>

===================================================

Work Shown:

LCM = least common denominator

List out the prime factorization of each denominator

6 = 2*3
11 = 1*11
12 = 2*2*3

So we have the list of primes 2,3, and 11 that help form the denominators when we multiply some of them together.

The prime 2 shows up at most twice, so 2*2 = 4 is a factor of the LCM

The prime 3 shows up at most one time, meaning 3 is also a factor

The prime 11 shows up at most one time, so 11 is another factor

Multiply these factors to get 4*3*11 = 12*11 = 132

The LCM is 132

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Another Approach:

Focus on 1/6 and 10/11 for now. The LCM is 66 because 6*11 = 66. We simply multiply the denominators together. Then we divide over the GCF 1 to get 66/1 = 66.

The LCM of 1/6 and 10/11 is 66

The fractions 1/6 and 10/11 are equivalent to 11/66 and 60/66 respectively

The original list of fractions updates to 11/66, 60/66, 5/12

We've gone from 3 different denominators to now 2 different denominators.

Repeat the steps of multiplying the denominators and dividing by the GCF

66*12 = 792

792/(gcf of 66 and 12) = 792/6 = 132

So the LCM of all the fractions is 132.

3 0

4 years ago

∠G and ∠H are supplementary; m∠G = (x + 4)° and m∠H = (4x + 11)°. What is the measure of ∠G? What is the measure of ∠H?

iogann1982 [59]

Answer:

∠G = 37°

∠H = 143°

Step-by-step explanation:

As we know ,

Sum of supplementary angles is 180 degrees.

Hence sum of ∠G and ∠H is also 180 degrees

∠G + ∠H = 180

Substituting the given values in above equation, we get -

$(X+4) + (4X +11) = 180\\5X + 15 = 180\\5X = 165\\X = 33$

∠G = (x + 4)° = (33 + 4)° = 37°

∠H = (4x + 11)° = (33*4 + 11)° = 143°

3 0

2 years ago

Ted and Jude are each saving money each month. After x months, the amount of money, in dollars, that Ted has saved is represente

Nadusha1986 [10]

Answer:

True Statements are -

B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

Step-by-step explanation:

Given - Ted and Jude are each saving money each month. After x months, the amount of money, in dollars, that Ted has saved is represented by the

equation T = 40x, and the amount of money that Jude has saved is represented by the equation J = 60x.

To find - Choose all of the statements that are true.

A. Each month, Jude saves two-thirds as much money as Ted saves.

B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

C. The amount of money Jude saves each month is $20 more than the amount Ted saves each month.

D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

Proof -

Given that,

After x months,

Ted saved the amount of money, T(x) = 40x

Jude saved the amount of money, J(x) = 60x

Now,

In 1 month,

Ted saved money, T(1) = 40(1) = 40

Jude saved money, J(1) = 60(1) = 60

So,

In 1st month, Jude saved money 20 more than Ted saved.

Now,

In 2 month,

Ted saved money, T(2) = 40(2) = 80

Jude saved money, J(2) = 60(2) = 120

So,

In 2nd month, Jude saved money 40 more than Ted saved.

Now,

In 3 month,

Ted saved money, T(3) = 40(3) = 120

Jude saved money, J(3) = 60(3) = 180

So,

In 3rd month, Jude saved money 60 more than Ted saved.

So,

Option C is incorrect

Because

In 1st month, Jude saves is $20 more than the amount Ted saves

In 2nd month, Jude saves is $40 more than the amount Ted saves

Now,

In 1st month,

Ted saves = 40

and

$\frac{2}{3}(40)$ = 26.67

So, Jude will save = 40 + 26.67 = 66.67

But Jude saves 60

So,

Option A is incorrect.

i.e. A. Each month, Jude saves two-thirds as much money as Ted saves.

Now,

We can see that,

In 3 months, Ted will have saved the money = 120

In 2 months, Jude will have saved the money = 120

So,

Option B is correct.

i.e. B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

Also,

We can see that

In 1st month, Jude saved money 20 more than Ted saved.

In 2nd month, Jude saved money 40 more than Ted saved.

In 3rd month, Jude saved money 60 more than Ted saved.

So,

Option D is correct.

i.e. D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

∴ we get

True Statements are -

B. In 3 months, Ted will have saved the same amount that Jude saved in 2 months.

D. The total amount of money Jude has saved is always $20 more than the total amount Ted has saved.

7 0

3 years ago

Need answer!! please help.

defon

Answer:

I think A

Step-by-step explanation:

8 0

3 years ago