This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π

4 0

3 years ago

Read 2 more answers

Find the quotient and remainder when p (x) divides with g (x) question (i) P (x) = x raise to 4 - 3 x square +4x + 5, g (x) = x

Morgarella [4.7K]

Answer: $x^2-8+\dfrac{4x+5}{x^4-3x^2+4x+5}$

Step-by-step explanation:

P(x) = x⁴ - 3x² + 4x + 5

g(x) = x² + 5

_x²_- 8

x² + 5) x⁴ + 0x³ - 3x² + 4x + 5

-(x⁴ + 0x³ + 5x²) ↓ ↓

-8x² + 4x + 5

-(-8x² + 0x - 40)

4x + 45

$\dfrac{x^4-3x^2+4x+5}{x^2+5}=\large\boxed{x^2-8+\dfrac{4x+5}{x^4-3x^2+4x+5}}$

5 0

4 years ago

Help please its a grade :)

stepladder [879]

Answer:

Step-by-step explanation:

A histogram displays frequencies of ranges; for example, in the given picture, in the range $[0, 2)$ (including zero, excluding two), there are zero values.