Does a equilateral have the same properties as as an isosceles triangle

1 answer:

5 0

No, equilateral triangles and isosceles triangles are 2 different things, equilateral triangles have all equals sides and angles (all angle measurements would be 60 degrees) and isosceles triangles have only 2 sides of equal measurements and one is different from the other 2. Hope I helped :)

You might be interested in

Will give brainliest and extra points if help

stira [4]

Answer: c

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What’s 4d plus 12e in distributive property

jeka57 [31]

I am not 100% certain but i believe it goes as follows:

4 ( 1 + d ) + ( 3 + e)
4d + 12e

6 0

3 years ago

Need to find out a mix number or fraction of %116

enyata [817]

116%
=1.16
=1 16/100
=1 4/25

7 0

3 years ago

How many times can 3 go into 84

satela [25.4K]

well, 84 divided by 3 is 28 and if you check that by multiplying 28 with 3 you get 84 so its 28

8 0

4 years ago

Read 2 more answers

Evaluate the limit of

tekilochka [14]

Answer:

Option a is correct -- $\frac{9}{2}$

Step-by-step explanation:

If we put infinity directly into the expression we get ∞ + ∞ expression. In order to circumvent it we divide both numerator and denominator with the greatest exponent.

$\lim_{x \to \infty} \frac{9n^{3}+5n-2}{2n^{3}}$

Divide each term by n³

$=\lim_{x \to \infty} \frac{\frac{9n^{3}}{n^{3}}+\frac{5n}{n^{3}} -\frac{2}{n^{3}}}{\frac{2n^{3}}{n^{3}} }$

$=\lim_{x \to \infty}\frac{9(1)+\frac{5}{n^{2}}-\frac{2}{n^{3}}}{2(1)} } \\=\lim_{x \to \infty}\frac{9+\frac{5}{n^{2}}-\frac{2}{n^{3}}}{2}} \\\\by putting n = infinity \frac{5}{n^{2}} becomes 0 and\frac{2}{n^{3}} becomes 0 \\=\frac{9+0-0}{2} \\=\frac{9}{2}$

4 0

4 years ago