The function of the object height is an illustration of a projectile motion
The object will never hit the ground
<h3>How to determine when the object hits the ground?</h3>
The function is given as:
h=16t^2+80t+96.
When the object hits the ground, h = 0
So, we have:
16t^2+80t+96 = 0
Divide through by 16
t^2+5t+6 = 0
Expand
t^2 + 3t + 2t + 6 = 0
Factorize
t(t + 3) + 2(t + 3) = 0
Factor out t + 3
(t + 2)(t + 3) = 0
Solve for t
t = -2 or t = -3
The time (t) cannot be negative.
Hence, the object will never hit the ground
Read more about projectile motion at:
brainly.com/question/1130127
Answer:
4 meters/ sec
Step-by-step explanation:
20/5 = 4 Lol
Pls mark brainliest
Answer:
Step-by-step explanation:
Answer:
c
Step-by-step explanation
because 2 is the y intercept and 3 is the slope so you plot (0,2) than do the slope.
Answer:
x-y+16
Step-by-step explanation:
add the like terms, 6 and 10 which is 16. since the variables are not like terms, thats your final answer. hope it helped :)
