If the coefficient of static friction is 0.3, then the minimum force required to get it moving is equal in magnitude to the maximum static friction that can hold the body in place.
By Newton's second law,
• the net vertical force is 0, since the body doesn't move up or down, and in particular
∑ <em>F</em> = <em>n</em> - <em>mg</em> = <em>n</em> - 50 N = 0 ==> <em>n</em> = 50 N
where <em>n</em> is the magnitude of the normal force; and
• the net horizontal force is also 0, since static friction keeps the body from moving, with
∑ <em>F</em> = <em>F'</em> - <em>f</em> = <em>F'</em> - <em>µn</em> = <em>F'</em> - 0.3 (50 N) = 0 ==> <em>F'</em> = 15 N
where <em>F'</em> is the magnitude of the applied force, <em>f</em> is the magnitude of static friction, and <em>µ</em> is the friction coefficient.
Answer:
It should be (A few centimeters per year) About three to five centimeters
The spring constant is 
Explanation:
For an object in a simple harmonic motion, the acceleration of the object is related to the displacement by

where
a is the acceleration
is the angular frequency
x is the displacement
The angular frequency is defined as

where
k is the spring constant
m is the mass
Substituting the second equation into the first one, we get

In this problem we have
m = 1 g = 0.001 kg
And at t=0,
x = 43.75 cm
a = -1.754 cm/s
Therefore, we can re-arrange the equation above to find the spring constant:

#LearnwithBrainly
Answer
given,
SAT is 500 with a standard deviation of 100.
a sample of 400 students whose family income was between $70,000 and $80,000 had an average verbal SAT score of 511.
sample mean = 
= 
= 5
95% confidence level is achieved within +/- 1.960 standard deviations.
1.960 standard deviations x 5 is equal to +/- 9.8
confidence interval = 511 - 9.8 --- 511 + 9.8
= 501.2-----520.8
<span> velocity increases by √3</span>