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Fudgin [204]
3 years ago
14

It is known that the population mean for the verbal section of the SAT is 500 with a standard deviation of 100. In 2006, a sampl

e of 400 students whose family income was between $70,000 and $80,000 had an average verbal SAT score of 511. The point estimate of the mean for this group is _____ and the 95 percent confidence interval for this group is _____.
Physics
1 answer:
kvasek [131]3 years ago
4 0

Answer

given,

SAT is 500 with a standard deviation of 100.

a sample of 400 students whose family income was between $70,000 and $80,000 had an average verbal SAT score of 511.

sample mean = \dfrac{standard\ deviation}{\sqrt{n}}

                      = \dfrac{100}{\sqrt{400}}

                      = 5

95% confidence level is achieved within +/- 1.960 standard deviations.

1.960 standard deviations  x  5 is equal to +/- 9.8

confidence interval = 511 - 9.8   ---  511 + 9.8

                                = 501.2-----520.8

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B. Kinetic energy plus its potential energy.
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Answer:

Explanation:

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s = (18² - 12²) / (2(3))

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to verify we can see that the acceleration time is

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A camcorder has a power rating of 11 watts. If the output voltage from its battery is 3 volts, what current does it use? amps
sergey [27]
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4 0
3 years ago
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A 1-hectare field contains 2500 bean plants having a total leaf surface area of 557 m2. ambient temperature is 21°c, winds are
Mashcka [7]

Answer:

The field losses a total of 55.814 litres of water in an hour.

Explanation:

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Now the average rate of water loss per minute is 1.67 mL/m2

So the average rate of water loss per minute for 557 m2 is 1.67*557=930.19 mL

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8 0
3 years ago
A star near the visible edge of a galaxy travels in a uniform circular orbit. It is 41,200 ly (light-years) from the galactic ce
Ronch [10]

The total mass of the galaxy is 443.4 Solar mass

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where M= weight of galaxy

G= gravitational constatnt = 6.674*10^-^1^1 (given)

R = distance from centre = 41200 Light years (given)= 4.12*9.5*10^1^6  km (1 ly= 9.5*10^3 billion km)

v= orbital velocity = 275  km/s (given)

∴ According to the formula

(2.75*10^2)^2 = \frac{M*6.674*10^-^1^1}{4.12*9.5*10^1^6}

⇒ 7.56*10^4*4.12*9.5*10^1^6=M*6.674*10^-^1^1 (cross multiplying and expanding)

⇒ 29.59*10^2^1=M*6.674*10^-^1^1

⇒ \frac{29.59*10^2^1*10^1^1}{6.674}=M

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⇒ M = 443.4 Solar mass

Learn more about Orbital velocity here :

brainly.com/question/22247460

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