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Answer and working shown on photo
Answer:
h = 1.07 m
Explanation:
It is given that,
The average sped of the kingfisher, v = 4.6 m/s
Time, t = 1.4 s
Final speed, v = 0 (as it hits the water)
We need to find the height from which the bird dove. Let the height is h. According to the conservation of energy.
So, the bird dove from a height of 1.07 m.
Explanation:
The law of repulsion is given by Coulomb. The mathematical form of Coulomb law is given by :
...............(1)
Where
F is the force
k is the electrostatic constant
are electric charges
r is the distance between charges
The Newton's law of universal gravitation is given by :
..............(2)
G is the universal gravitational constant
From equation (1) and (2) it is clear that both law obeys inverse square law and both are of same type. So, the law of repulsion by Coulomb agrees with the Newton's law of universal gravitation.