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valkas [14]
3 years ago
11

While skiing, Sam flies down a hill and hits a jump. He has a mass of 75 kg, and he leaves the jump at 18 m/s. What is his momen

tum as he leaves the jump?
Physics
2 answers:
Evgen [1.6K]3 years ago
6 0

For this you would use the equation P = M x V

P ( momentum )

M ( mass - kg)

V ( velocity -m/s )

____________

Sams mass is 75 kg so you would fill in the "m" spot with 75

Sams velocity is 18 so you'd fill in the "v" spot with 18

_____

Your equation should look like this:

P = 75 x 18

From here is simple multiplication

75 x 18 = 675

Therefore your answer is p = 675

Vinvika [58]3 years ago
3 0
P=mv=18*75=1350
.......
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Which instrument changes kinetic energy into electrical energy?
Pachacha [2.7K]

Answer:

Dynamo

Explanation:

Dynamo started to rotate which is known as kinetic energy.When dynamo is in running it produces electricity.dynamo specially used for generating electricity.

5 0
3 years ago
A fighter jet accelerates from 10 m/s to 75 m/s in 7.0 s. The acceleration of the jet is
liraira [26]
Acceleration = final velocity - inital / time
a = 75-10 / 7
a = 65 / 7
a = 9.29 m/s^2

4 0
3 years ago
What is 1113.28 in a sig fig?
Afina-wow [57]

Answer:

6 significant figure

Explanation:

The digits 111328 all are 6 figures with no figure being zero, neither zero after the other digits. In this case, all the numbers are significant and since they are only six numbers, then this is a six significant figure. In case we add another zero after digit 8, the zero is not significant but if added either infront of 8 or 2, the zero becomes significant.

4 0
3 years ago
WILL GIVE BRAINLIEST PLEASE ANSWER ALL QUESTIONS
Rainbow [258]
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5 0
2 years ago
You observe that a mass suspended by a spring takes 0.25 s to make a full oscillation. What is the frequency of this oscillation
Katarina [22]

Answer:

Frequency of oscillation, f = 4 Hz

time period, T = 0.25 s

Angular frequency, \omega = 25.13 rad/s

Given:

Time taken to make one oscillation, T = 0.25 s

Solution:

Frequency, f of oscillation is given as the reciprocal of time taken for one oscillation and is given by:

f = \frac{1}{T}

f = \frac{1}{0.25}

Frequency of oscillation, f = 4 Hz

The period of oscillation can be defined as the time taken by the suspended mass for completion of one oscillation.

Therefore, time period, T = 0.25 s

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\omega = 25.13 rad/s

5 0
3 years ago
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