Answer:
3.50*10^-11 mol3 dm-9
Explanation:
A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential difference between the rod and the SHE is 0.5812 V, the rod being positive. Calculate the solubility product constant for silver oxalate.
Ag2C2O4 --> 2Ag+ + C2O4 2-
So Ksp = [Ag+]^2 * [C2O42-]
In 1 L, 2.06*10^-4 mol of silver oxalate dissolve, giving, the same number of mol of oxalate ions, and twice the number of mol (4.12*10^-4) of silver ions.
So Ksp = (4.12*10^-4)^2 * (2.06*10^-4)
= 3.50*10^-11 mol3 dm-9
Freezing point is the temperature at which a substance undergoes a phase transition from liquid to solid state. Water converts from liquid state to solid ice at a temperature of 
.
Mass is the amount of matter contained in a substance. The SI unit of mass is kilogram. 1 kilogram is equal to 1000 g. One kilogram is defined as the mass of one cubic decimeter of water at the freezing point of water.
Answer:
It reacts explosively with oxygen.
Explanation:
Reactivity is a chemical property.
Taste, temperature, and density are all chemical properties.
(B) Radiation
At the quantum level electromagneticradiation radiation is produced when the wavepacket of a charged particle oscillates or otherwise accelerates
