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Nitella [24]
4 years ago
6

Simplify sec(arcsec 1/2). A. undefined B. -1/2 C. 1/2 D. 2

Mathematics
2 answers:
kirill [66]4 years ago
8 0
\bf \textit{what is the sine of }90^o?\qquad 1\textit{ then what is the }sin^{-1}(1)?\quad 90^o
\\\\\\
\textit{now then, what is }sin(~~sin^{-1}(1)~~)?\textit{ is just }1\\\\
-------------------------------\\\\

\bf likewise\qquad 
\begin{cases}
cos(~~cos^{-1}(whatever)~~)\implies  whatever\\
sin(~~sin^{-1}(whatever)~~)\implies  whatever\\
tan(~~tan^{-1}(whatever)~~)\implies  whatever\\
cot(~~cot^{-1}(whatever)~~)\implies whatever\\
sec(~~sec^{-1}(whatever)~~)\implies  whatever\\
csc(~~csc^{-1}(whatever)~~)\implies  whatever
\end{cases}

so, surely you know what that is then.
sukhopar [10]4 years ago
3 0
C.1/2 is answer number
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4 years ago
It takes Maya 2 1/2 hours to make cupcakes each batch of cupcakes takes 3/4 of an hour how many batches of cupcakes can she make
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Since 1 hour is equal to 3/4 Batch of cupcakes, then you would have to divide
5 0
3 years ago
Perform the indicated operation.
Ivanshal [37]

Answer Solution:4x2 - 2x) - (-5x2 - 8x)

4x2 - 2x) - (-5x2 - 8x)= 4x2 - 2x + 5x2 + 8x.

4x2 - 2x) - (-5x2 - 8x)= 4x2 - 2x + 5x2 + 8x.= 4x2 + 5x2 - 2x + 8x.

4x2 - 2x) - (-5x2 - 8x)= 4x2 - 2x + 5x2 + 8x.= 4x2 + 5x2 - 2x + 8x.= 9x2 + 6x.

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5 0
3 years ago
Read 2 more answers
Please help i’m stuck!!<br> FIND GE AND FJ<br> HE = 6<br> FE= 8
dexar [7]

Answer:

GE=10

FJ=5

Step-by-step explanation:

We know that in a traingle

a^{2}+b^{2}  =c^{2}

a=HE=6

b=FE=8

Once we enter it into the equation, we find that we get

36+64=100

The square root of 100=10

GE=HF so HE=10.

Half of HE(10) is FJ(5)

Hope this help :)

6 0
3 years ago
A restaurant offers a catering service which costs $25.00 per person with a $119.50 service charge. For parties of 50 or more pe
Molodets [167]

Answer:

T1(n) = 25n +119.50  where n belongs to 1 \leq n.

T2(n) = 20n + 59 where n belongs to 50\leq  n.

Step-by-step explanation:

We are given two situations first is for normal days and the other is for days when 50 or more people are going to this restaurant for the party.

Let the number of person going for this restaurant be "n"

For normal day, we are given

catering service = $25 per person

service charge = $119.50  

Let the total cost of the restaurant be T

Cost for this case will be T1  

T1(n) = 25n +119.50  where n belongs to 1 \leq n

similarly for the case when 50 or more than that goes to this restaurant for party.

cost after discount

Catering service = $20.00 per person

service charge = $59.00

now the cost of this case will be T2

T2(n) = 20n + 59 where n belongs to 50\leq  n.

Therefore the two piecewise linear functions represents the total cost of the restaurant for serving n people.  

7 0
3 years ago
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