Answer:
P(Y=1|X=3)=0.125
Step-by-step explanation:
Given :
p(1,1)=0
p(2,1)=0.1
p(3,1)=0.05
p(1,2)=0.05
p(2,2)=0.3
p(3,2)=0.1
p(1,3)=0.05
p(2,3)=0.1
p(3,3)=0.25
Now we are supposed to find the conditional mass function of Y given X=3 : P(Y=1|X=3)
P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)
P(X=3)=p(3,1) +p(3,2) +p(3,3)
P(X=3)=0.05+0.1+0.25=0.4

Hence P(Y=1|X=3)=0.125
Answer:
-4, -2, 0, 2
Step-by-step explanation:
the expression for the integers are; x, x +2, x + 4, x + 6
4x + 12 = -4
4x = -16
x = - 4
your integers are; -4, -2, 0, 2
if you add those your answer will be -4
Answer:
.
Step-by-step explanation:
Let x represent height of the cone.
We have been given that Sand pouring from a chute forms a conical pile whose height is always equal to the diameter.
We know that radius is half the diameter, so radius of cone would be
.
We will use volume of cone formula to solve our given problem.

Upon substituting the value of height and radius in terms of x, we will get:



Now, we will take the derivative of volume with respect to time as:


Upon substituting
and
, we will get:




Therefore, the sand is pouring from the chute at a rate of
.