Answer:

Step-by-step explanation:
To find the inverse of a function, what I like to do is to switch the places of x and y, and then try to isolate y again like so:



Hope this helps!
Let c = hypotenuse and a = leg 1 and b = leg 2. If c² > a² + b², then it is obtuse. If it is less, then it is acute. I hope it helps.
It’s a triangle
s
r t
rs= 2x+10 and st= x-4
the sides are equal so equal them together then solve
2x+10=x-4
+ 4 +4
2x+14=x
you got x alone so x=2x+14
now you plug in 2x+14 in for the x in rs and st
rs= 2(2x+14)+10
4x+28+10
4x+38
st= (2x+14)-4
2x+14-4
2x-10
Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
obtuse angle
Step-by-step explanation: