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alexira [117]
3 years ago
10

0.2.0.4, 0.6, 0.8, 1.... Arithmetic or geometric

Mathematics
1 answer:
Basile [38]3 years ago
3 0

Arithmetic sequences have a common difference between consecutive terms.

Geometric sequences have a common ratio between consecutive terms.

Let's compute the differences and ratios between consecutive terms:

Differences:

0.4-0.2 = 0.2,\quad 0.6-0.4=0.2,\quad 0.8-0.6=0.2,\quad 1-0.8=0.2

Ratios:

\dfrac{0.4}{0.2}=2,\quad \dfrac{0.6}{0.4} = 1.5,\quad \dfrac{0.8}{0.6} = 1.33\ldots, \quad\dfrac{1}{0.8}=1.25

So, as you can see, the differences between consecutive terms are constant, whereas ratios vary.

So, this is an arithmetic sequence.

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14 minus 48 plus 93 divided by -95​
ankoles [38]

Answer:

The answer would be -35.

Step-by-step explanation: (14-48) + (93 DIVIDED BY (-95))= -34.9789473684 WHICH ROUNDS OUT TO BE -35.

7 0
3 years ago
Which equation represents a population of 210 animals that decreases at an annual rate of 14%
soldi70 [24.7K]

Answer:

The equation i.e. used to denote the population after x years is:

P(x) = 490(1 + 0.200 to the power of x

Step-by-step explanation:

This problem could be modeled with the help of a exponential function.

The exponential function is given by:

P(x) = ab to the power of x

where a is the initial value.

and b=1+r where r is the rate of increase or decrease.

Here the initial population of the animals are given by: 490

i.e. a=490

Also, the rate of increase is: 20%

i.e. r=20%

i.e. r=0.20

Hence, the population function i.e. the population of the animals after x years is:

P(x) = 490(1 + 0.200 to the power of x

6 0
3 years ago
the table below shows the function of f determine the value of f(3) that will lead to an average rate of change of 19 over the i
3241004551 [841]

ANSWER

f(3) =  - 25

EXPLANATION

We want to determine the value of f(3) that will lead to an average rate of change of 19 over the interval [3, 5].

The average rate of change of f(x) over the interval [a,b]:

=  \frac{f(b) - f(a)}{b - a}

If the average rate of change over the interval [3, 5] is 19, then;

\frac{f(5) - f(3)}{5 - 3}  = 19

From the to table f(5)=13

\frac{13 - f(3)}{2}  = 19

13 - f(3) = 19 \times 2

13 - f(3) = 38

- f(3) = 38 - 13

- f(3) = 25

f(3) =  - 25

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Answer:

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Step-by-step explanation:

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