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Akimi4 [234]
2 years ago
7

If you have a density of 100kg/L and a mass of 1000 units, tell me the following: second what is the volume

Physics
1 answer:
adell [148]2 years ago
8 0

Answer:

volume is 0.1 L

Explanation:

you can use the equation density=mass/volume

100 = 1000 / v

divide by 1000 on both sides

0.1 = v

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Describe a vector and how it is used​
Ilia_Sergeevich [38]

Answer:

Vectors are used in science to describe anything that has both a direction and a magnitude. They are usually drawn as pointed arrows, the length of which represents the vector's magnitude.

Explanation:

They are usually drawn as pointed arrows, the length of which represents

8 0
3 years ago
What is the rate of acceleration due to gravity on Earth?
Katena32 [7]

Answer:

Negative 9.8 meters per second squared

Explanation:

The negative is for the direction (down, towards the center of the earth). Often this can be estimated as -10 m/s^2 to make calculations easier.

3 0
3 years ago
arzan, who weighs 700 N, swings from a cliff at the end of a convenient vine thatis 20 m long. From the top of the cliff to the
vekshin1

Answer:

= 7.07 m

Explanation:

The Tarzan reaches bottom of swing after descending 2.5 m,

change in his potential energy equals his kinetic energy at bottom of swing

m g h = (1/2) m v²   ,  

hence speed v of Tarzan at bottom of swing is given as  

v = ( 2 g h )1/2

= ( 2 × 9.8 × 2.5 )1/2

= 7 m/s

At the bottom of swing, if the vine breaks, then he is moving with horizontal velocity 7 m/s in gravitational field.  

If vertical distance from ground to bottom of swing is 5 m, then time t for Tarzan to reach ground is given by

S = (1/2)g t2 or   t = (2S/g)1/2

= ( 2 × 5 / 9.8 )1/2

= 1.01 s

Horizontal distance traveled by Tarzan = 1.01 × 7

= 7.07 m

7 0
2 years ago
The component of the ball's velocity whose magnitude is most affected by the collisions is
bazaltina [42]
<span>The component most affected by the collisions is vertical. The ball's vertical will either decrease or increase due to the collision. If the velocity is high during the collsion the ball's vertical will likely be higher and if the ball's velocity is low the vertical will be as well.</span>
8 0
3 years ago
a 1.2 kg rocket is launched from ground level with initial velocity of 12 m/s. What is the maximum height the rocket can reach?
Tanzania [10]

As the rocket is launched from the ground its height will go on increasing till it stops

So the height of rocket will be maximum when its speed becomes zero

so here we can use energy conservation theory

PE = KE

mgH = \frac{1}{2}mv^2

9.8*H = \frac{1}{2}*12^2

H = 7.35 m

So it will reach upto height 7.35 m

5 0
2 years ago
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