An ac generator with peak voltage 100 volts is placed across a 10-? resistor. What is the average power dissipated?

1 answer:

3 0

The correct answer is: Average Power = 500 W

Explanation:
Root-mean square voltage = Vrms = Vpeak /√2 = 100 / √2 volts
Resistance = R = 10 Ω
Average power = Pavg = (Vrms)^2<span> / R </span>= (100 * 100) / (2 * 10) = <span>500 W</span>

You might be interested in

What property is an acid-base indicator used to measure?

Volgvan

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

What material of mass 39g,has a volume of 5cm^3

insens350 [35]

The material of density 7.8 g/cm³

4 0

2 years ago

Help me plz i'll mark brainliest

HACTEHA [7]

Answer:

a PDF is what u use to upload an assignment to turn it in to get graded

8 0

2 years ago

after the car leaves the platform , gravity causes it to accelerate downward at a rate of 9.8 m/s2. what is the gravitational fo

alexandr1967 [171]

The gravitational force on the car is the force popularly known
as the car's "weight". Its magnitude is

(9.8 m/s²) times (the car's mass, in kilograms) .

The unit of this quantity is [newton] .

5 0

2 years ago

Air enters a compressor with a pressure of 14.7 lbf/in.2 , a temperature of 70F, and a volumetric flow rate of 40 ft3 /s. Air ex

disa [49]

Answer:

210 hp

Explanation:

See attached picture.

3 0

2 years ago