An ac generator with peak voltage 100 volts is placed across a 10-? resistor. What is the average power dissipated?

1 answer:

3 0

The correct answer is: Average Power = 500 W

Explanation:
Root-mean square voltage = Vrms = Vpeak /√2 = 100 / √2 volts
Resistance = R = 10 Ω
Average power = Pavg = (Vrms)^2 / R = (100 * 100) / (2 * 10) = 500 W

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