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Tpy6a [65]
3 years ago
13

An ac generator with peak voltage 100 volts is placed across a 10-? resistor. What is the average power dissipated?

Physics
1 answer:
Romashka [77]3 years ago
3 0
The correct answer is: Average Power  = 500 W

Explanation:
Root-mean square voltage = Vrms = Vpeak /√2 = 100 / √2 volts
Resistance = R = 10 Ω
Average power = Pavg = (Vrms)^2<span> / R </span>= (100 * 100) / (2 * 10) = <span>500 W</span>
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