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3 years ago

The

Physics

1 answer:

USPshnik [31]3 years ago

3 0

Answer:

Point of operation.

Explanation:

A tool can be defined as a mechanical or electronic apparatus that is typically used for performance of specific tasks.

This ultimately implies that, a tool is generally used by workers to perform their day-to-day tasks, duties or job functions.

All work related activities in the workshop have a point of operation i.e the particular point where a task is to be performed such as cutting a wood.

Hence, the point of operation is where the worker applies a tool to materials.

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A 3.00-kg model airplane has velocity components of 5.00 m/s due east and 8.00 m/s due north. What is the plane’s kinetic energy

GalinKa [24]

Answer:

Kinetic energy, E = 133.38 Joules

Explanation:

It is given that,

Mass of the model airplane, m = 3 kg

Velocity component, v₁ = 5 m/s (due east)

Velocity component, v₂ = 8 m/s (due north)

Let v is the resultant of velocity. It is given by :

$v=\sqrt{v_1^2+v_2^2}$

$v=\sqrt{5^2+8^2}=9.43\ m/s$

Let E is the kinetic energy of the plane. It is given by :

$E=\dfrac{1}{2}mv^2$

$E=\dfrac{1}{2}\times 3\ kg\times (9.43\ m/s)^2$

E = 133.38 Joules

So, the kinetic energy of the plane is 133.38 Joules. Hence, this is the required solution.

5 0

3 years ago

Read 2 more answers

SIEVERT (SV) IS THE PRODUCT OF ABSORBED DOSE AND RADIATION WEIGHTING FACTOR<br> T True<br> F False

Alla [95]

Answer:

False

Explanation:

Sievert is the unit of dose equivalent

4 0

3 years ago

Which of the following does not have a global cycle?

Darya [45]

The answer is c hope it helps

8 0

3 years ago

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In 1935, a French destroyer, La Terrible, attained one of the fastest speeds for any standard warship. Suppose it took 3.0 min a

REY [17]

Answer:

Explanation:

From newton's equation of motion of uniform acceleration

v = u + at

where v is final velocity , u is initial velocity , a is acceleration and time is t .

putting the values

v = 0 + .5 x 3 x 60 ( time in second = 3 x 60 s )

= 90 m /s

So , final velocity is 90 m /s .

7 0

4 years ago

Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.

Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

r = $\frac{mv}{qB}$

Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r = $\frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T}$ = 0.0328 m, or 3.28 cm.

8 0

3 years ago