Independent assessment 3

a jet bomber traveling 500 mph arrived over its Target at the same time as its fighter jet escorted which left the same fate 2.5

vlada-n [284]

Since the jet bomber arrived over its Target at the same time as its fighter jet escorted, it took the jet bomber 0.34 h to reach the target.

<h3 />

To find the number of hours, we need to solve simultaneous equations.

<h3>What are simultaneous equations?</h3>

Simultaneous equations are pair of equations which contain two unknowns.

<h3>How to calculate the number of hours the bomber jet took off?</h3>

Let

D = distance travelled by both bomber jet and fighter jet.
t = time bomber jet took off
v = speed of bomber jet.
T = time fighter jet took off and
V = speed of fighter jet.

So, D = vt

D = 500t (1)

Also, D = VT

D = 60T (2)

Since jet bomber traveling 500 mph arrived over its Target at the same time as its fighter jet escorted which left the same fate 2.5 hours after the bomb took off.

T = t + 2.5

So, D = 60(t + 2.5) (3)

<h3>The required simultaneous equations</h3>

D = 500t (1)

D = 60(t + 2.5) (3)

Equating equations (1) and (3), we have

500t = 60(t + 2.5)

500t = 60t + 150

500t - 60t = 150

440t = 150

t = 150/440

t = 15/44

t = 0.34 h

So, it took the jet bomber 0.34 hours to reach the target.

Learn more about simultaneous equations here:

brainly.com/question/27829171

#SPJ1

8 0

2 years ago

Suppose \nabla f (x,y) = 3 y \sin(xy) \vec{i} + 3 x \sin(xy)\vec{j}, \vec{f} = \nabla f(x,y), and c is the segment of the parabo

Anna11 [10]

I'll assume you're supposed to compute the line integral of $\nabla f$ over the given path $C$ . By the fundamental theorem of calculus,

$\displaystyle\int_C\nabla f(x,y)\cdot\mathrm d\vec r=f(4,48)-f(1,3)$

so evaluating the integral is as simple as evaluting $f$ at the endpoints of $C$ . But first we need to determine $f$ given its gradient.

We have

$\dfrac{\partial f}{\partial x}=3y\sin(xy)\implies f(x,y)=-3\cos(xy)+g(y)$

Differentiating with respect to $y$ gives

$\dfrac{\partial f}{\partial y}=3x\sin(xy)=3x\sin(xy)+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C$

and we end up with

$f(x,y)=-3\cos(xy)+C$

for some constant $C$ . Then the value of the line integral is $-3\cos192+3\cos3$ .

8 0

4 years ago

That sounds like a good deal, but how about I give you 10 points for an answer.

Ilia_Sergeevich [38]

The answer is A - 1
Hope it helped

3 0

3 years ago

Read 2 more answers

11. Find the roots of x2 - 8x + 4 = 0, in simplest radical form.

Art [367]

Answer: -6=-4 or x=2,3

Step-by-step explanation:

8 0

3 years ago

Lily likes to collect records. Last year she had 10 records in her collection. Now she has 15 records. What is the percent incre

Cloud [144]

Well if the original number is 10 and now it’s 15 that would make the percentage of increase 0.5%

8 0

3 years ago