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V125BC [204]
4 years ago
15

Is y= x2-1 a linear equation

Mathematics
1 answer:
kotegsom [21]4 years ago
3 0

Answer: With the way you wrote it, I don't know. I'm assuming that it's y=x^2+1. If that's the case, then no it's not linear.

Step-by-step explanation:

It's not a straight line. Graph it.

It's frustrating seeing questions like yours where the person asking literally does not even think through about their question. Next time, at least try the problem on your own instead of just deciding that you can't do it. This is an extremely easy problem, and I'm guessing you're just copying answers on here. The naivety here is palpable.

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Given p ≠ q ≠ 0, what is the equation of the line that passes through the points (–p, –q) and (p, q)?
liubo4ka [24]
Hey :))

(-p,-q)(p,q)slope = (q - (-q) / (p - (-p) = (q + q) / (p + p) = 2q / 2p = q/p
y = mx + b.....slope(m) = q/p(p,q)...x = p and y = qnow we sub and find b, the y intq = (q/p)(p) + bq = q + bq - q = b0 = b
so ur equation is : y = (q/p)x + 0...or just y = (q/p)x....its answer B
HOPE THIS HELPED!!!  :))
7 0
3 years ago
Read 2 more answers
Find the simplified product:<img src="https://tex.z-dn.net/?f=%5Csqrt%7B2x%5E%7B3%7D%20%7D-%5Csqrt%7B18x%5E%7B5%7D%20%7D" id="Te
mash [69]

Correct Question: Find the simplified product: \sqrt{2x^3}*\sqrt{18x^5}

Answer:

6x^4

Step-by-step explanation:

Based on the rules of radicals, since \sqrt{2x^3} and \sqrt{18x^5} has the same index (square root), therefore:

\sqrt{2x^3}*\sqrt{18x^5} = \sqrt{2x^3 * 18x^5}

To simplify this, multiply their bases together, and add their exponents.

= \sqrt{2*18x^{3+5}

= \sqrt{36x^{8}

Simplify further

= \sqrt{36}*\sqrt{x^8}

= \sqrt{6*6}*\sqrt{x^4*x^4}

= 6x^4

7 0
3 years ago
A triangle has side lengths of (8b – 10c) centimeters, (8b – 4d) centimeters, and
Leto [7]
Answer is b hope this helps
3 0
3 years ago
Read 2 more answers
If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
Jobisdone [24]
The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
6 0
3 years ago
Read 2 more answers
Surface Area of Cylinder=2πrh+2πr2
Alex

  • Find the surface area when r is 8 inches and h is 8 inches.

\qquad A. 160π in²

\qquad B. 154π in²

\qquad C. 288π in²

\qquad D. 256π in² ☑

We are given –

\qquad ⇢Radius of cylinder , r = 8 inches

\qquad⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }

Now, Substitute given values –

\sf  \twoheadrightarrow  Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 2 \pi \times 8 \times 8 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  =128 \pi + 128\pi

\purple{\bf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 256\pi \: in^2 }

  • Henceforth,Option D is the correct answer.

8 0
2 years ago
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