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4 years ago

How do i solve this? (1/3x-11)^(1/2)=5

2 answers:

5 0

Square both sides to get
(1/3x-11)=25
1/3x-11=25 then solve

why? because ^(1/2) means "take the square root". We need to "undo", or find the inverse so we square both sides.

photoshop1234 [79]4 years ago

4 0

$(\frac{1}{3} x-11)^{ \frac{1}{2} }=5\\ ((\frac{1}{3} x-11)^{ \frac{1}{2} })^{2}=(5)^{2}\\ \frac{1}{3} x-11=25\\ \frac{1}{3} x=36\\x=108$

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3 years ago

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Pipe A can fill a tank in 5 hours. Pipe B can fill the same tank in 7 hours. If both pipes were open, how long would it take the

-BARSIC- [3]

Answer:

It would take them 6 hours to fill an empty tank.

Step-by-step explanation:

Add the amount of time it takes Pipe A and Pipe B to fill an empty tank together (5 + 7) and then divide your sum by two. You should get 12 / 2 = 6.

<em>Hope This Helps!</em>

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2 years ago

Solve questions 15,16,17, and 18. Will give Brainliest!! Please!!! Show minimal work!

SVEN [57.7K]

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(0,-1).

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This implies that:

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16) We have that: $\cot \theta =-\frac{6}{7}$ .

We illustrate this on the right triangle and apply the Pythagoras Theorem as follows:

$h^2=6^2+7^2$

$h^2=36+49$

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$h=\sqrt{85}$

Using the mnemonics SOH-CAH-TOAH, we have:

$\sin \theta=-\frac{Opp}{Hyp}=-\frac{7}{\sqrt{85} }=-\frac{7\sqrt{85} }{85}$

$\cos \theta=\frac{Adj}{Hyp}=\frac{6}{\sqrt{85} }=\frac{6\sqrt{85} }{85}$

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17. We want to verify that: $sin^4x-sin^2x=cos^4x-cos^2x$

Verifying from the LHS

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$\sin^4x-sin^2x=(1-cos^2x)^2-(1-\cos^2x)$

$\sin^4x-sin^2x=1-2cos^2x+\cos^4x-1+\cos^2x$

$\sin^4x-sin^2x=\cos^4x-\cos^2x$

18. We have:

$\tan^2x\sec^2x+2\sec^2x-\tan^2x=2$

$\tan^2x\sec^2x+2\sec^2x-\tan^2x-2=0$

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When $(\sec^2x-1)=0$ , we have

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6 0

3 years ago

In the school parking lot there were 113 fewer bikes than cars. There were 185 cars. How many cars and bikes were there in the p

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There is 185 cars and bike is 72

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3 years ago

If the ratio of wiping is the green peas is 2 to 8 and there are a total of 30 pens how many pens are white

kaheart [24]

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hope this helped!

8 0

3 years ago