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White raven [17]
3 years ago
10

How do i solve this? (1/3x-11)^(1/2)=5

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
5 0
Square both sides to get
(1/3x-11)=25
1/3x-11=25 then solve

why? because ^(1/2) means "take the square root". We need to "undo", or find the inverse so we square both sides.
photoshop1234 [79]3 years ago
4 0
(\frac{1}{3} x-11)^{ \frac{1}{2} }=5\\ ((\frac{1}{3} x-11)^{ \frac{1}{2} })^{2}=(5)^{2}\\ \frac{1}{3} x-11=25\\ \frac{1}{3} x=36\\x=108
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Find a polynomial of degree 3 with a real coefficient that satisfies the given condition. Zeros: -2, 1, 0; f(2)=32
xz_007 [3.2K]
Its factors would be
(x+2)*(x-1)*(x+0)

x^2 +x -2

x^3 + 0 + x^2 + 0 -2x +0

Equation: x^3 + x^2 -2x
f(2) = 8 + 4 -4

2x^3  + 2x^2  -4x +0
f(2) = 16 + 8 -8

3x^3  + 3x^2  -6x +0
f(2) =  24 +12 -12

4x^3  + 4x^2  -8x +0
f(2) =  32 +16 -16

So, the equation is:
4x^3  + 4x^2  -8x = 0




8 0
3 years ago
What is the first term for an arithmetic sequence with a12 = 56 and a21=101?
Alenkinab [10]
The first term is -43.

Explanation:

an = a + (n - 1)d

a12 = a + 11d = 56, first equation
a21 = a + 20d = 101, second equation

Subtract the second equation from the first equation, cancelling +a and -a
11d - 20d = 56 - 101
-9d = -45
d = 5

Subtitute d into the first equation
a + 99 = 56
a = -43

a refers to the first term, hence the first term is -43.
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3 years ago
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Answer:

A is the correct answer

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Kyle was given the following question to solve.
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