The sum of the two <em>rational</em> equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).
<h3>How to simplify the addition between two rational equations</h3>
In this question we must use <em>algebra</em> definitions and theorems to simplify the addition of two <em>rational</em> equations into a <em>single rational</em> equation. Now we proceed to show the procedure of solution in detail:
- (n + 5) / (n² + 3 · n - 10) + 5 / (3 · n²) Given
- (n + 5) / [(n + 5) · (n - 2)] + 5 / (3 · n²) x² - (r₁ + r₂) · x + r₁ · r₂ = (x - r₁) · (x - r₂)
- 1 / (n - 2) + 5 / (3 · n²) Associative and modulative property / Existence of the multiplicative inverse
- [3 · n² + 5 · (n - 2)] / [3 · n² · (n - 2)] Addition of fractions with different denominator
- (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²) Distributive property / Power properties / Result
To learn more on rational equations: brainly.com/question/20850120
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Answer:
C) infinitely many solutions
Step-by-step explanation:
y= 3x-4
-3y= -9x +12
-3(3x-4 ) = -9x +12
-9x + 12 = -9x + 12
C) infinitely many solutions
Easy there on the caps, partner.
The nine, using the distributive property, distributes itself across the brackets, and so 9 times t is 9t and 9 times -1 is -9.
Therefore, 9(t-1) = 9t -9
The answer to 6 is repeating I believe
Answer:
4cm
Step-by-step explanation:
Given data
L=(2x+3)
W=(x-1)
P=28cm
A= L*W
A= (2x+3)*(x-1)
open bracket
A= 2x^2-2x+3x-3
collect like terms
A= 2x^2+x-3
P= 2L+2W
P= 2*(2x+3)+2(x-1)
P= 4x+6+2x-2
collect like terms
P= 6x-4
but p= 28
28= 6x-4
28-4= 6x
24= 6x
x= 24/6
x= 4cm
Hence x= 4cm
