In the figure, PA and PB are tangent to circle O and PD bisects ∠BPA . The figure is not drawn to scale. For m
1 answer:
Angle AOC = 46° Find angle BPO
We have congruent right triangles PAO and PBO, right angles A and B.
So AOC=BOC=46 degrees,
PBO is a right angle so BPO is complementary to BOC, so 42 degrees
Answer: 42 degrees
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