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djverab [1.8K]
2 years ago
7

What volume of a 0.50 m mgso4 solution will be needed to prepare 100.0 ml of a 0.20 m mgso4 solution?

Chemistry
1 answer:
enyata [817]2 years ago
7 0
The formula is given by Molarity of mgso4 required for the titration * Volume of mgso4 for the titration = Molarity of mgso4 used to make the solution * Volume of mgso4 used to make the solution. 
So we have 0.5 * Volume of mgso4 = 100 * 0.2 
So Volume of mgso4 = (100 * 0.2)/ 0.5 
Volume = 20/0.5 = 40ml = 40 * 10^(-3)
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Part A:
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Part A = The mass of sulfur is 6.228 grams

Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams

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Part A

Step 1: Data given

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