The density of a 167.4 g sample of magnesium having a volume of 96.32 ml is <u>1.737 g/cm3.</u>
<h3>What is density?</h3>
The mass per unit volume is known as density. A scalar quantity, density. It is represented by the letter D, and the Greek letter rho is used as the sign for density. Mass divided by volume is how density is computed.
Mass is a physical body's total amount of matter. Mass is defined as the sum of the moles of the material and the compound's molar mass.
Given the mass is 167.4 g
The volume is 96.32 ml
mass / volume
167.4 / 96.32 = 1.737
Thus, the density of a 167.4 g sample of magnesium is 1.737 g/cm3.
To learn more about density, refer to the link:
brainly.com/question/11105469
#SPJ4
Answer:
Mass of the ball is . 42 kg. The density of air is 1.2 kg/m3.
Explanation:
<h3>
Answer:</h3>
7.182K
<h3>
Explanation:</h3>
From the question we are given;
- Initial temperature, T1 = 275 K
- Final temperature, T2 = 395 K
- Initial volume, V1 = 5 L
We are required to calculate the final volume, V2
- Charles's law is the law that relates the volume of a gas and its temperature.
- It states that the volume of a fixed mass of a gas and its absolute temperature are directly proportional at a constant pressure.
- Therefore;
To calculate, V2 we rearrange the formula;
Therefore, the ending volume will be 7.182K
First, we need to get moles of HA =molarity * volume
= 0.1 m * 0.075 L = 0.0075 moles
moles of NaOH = molarity * volume
= 0.1 * 0.03 L = 0.003 moles
from the reaction equation:
HA(aq) + NaOH(aq) → NaA(aq) + H2O(l)
that means the final moles' HA = 0.0075 - 0.003 =0.0045 moles
when the total volume is = 0.075 + 0.03 L = 0.105 L
∴ [HA] = moles / volume
= 0.0045 / 0.105 L = 0.043 m
[A^-] = 0.003 / 0.105 L = 0.029 m
then by using H-H equation:
PH = Pka + ㏒[A^-] / [HA]
by substitution, we can get Pka:
5.5 = Pka+ ㏒ (0.029 /0.043)
∴ Pka = 5.67
when Pka = - ㏒Ka
5.67 = -㏒ Ka
∴Ka = 2 x 10^-6