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3 years ago

Which statement explains why low temperature and high pressure are required to liquefy chlorine gas?

Chemistry

2 answers:

Yanka [14]3 years ago

6 0

Answer: (3) Chlorine molecules have weak intermolecular forces of attraction.

Explanation: In order to liquefy a gas, the molecules must be brought closer. Chlorine being a gas has weak inter molecular forces of attraction and the molecules are far away from each other.

Thus decreasing the temperature would decrease the kinetic energy of the molecules and increase in pressure would bring the molecules close together to convert it into liquid phase.

Leona [35]3 years ago

3 0

4 is correct. Since gases are made of rapidly moving molecules with a relatively high amount of kinetic energy, the molecules have a hard time coming together to form a liquid. You must lower their kinetic energy with a low temperature and force the molecules together with high pressure.

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A reaction between substances Y and Z is

Anuta_ua [19.1K]

Answer : The value of activation energy for this reaction is 108.318 kJ/mol

Explanation :

The Arrhenius equation is written as:

$K=A\times e^{\frac{-Ea}{RT}}$

Taking logarithm on both the sides, we get:

$\ln k=-\frac{Ea}{RT}+\ln A$ ............(1)

where,

k = rate constant = $2.95\times 10^{-3}L/mol.s$

Ea = activation energy = ?

T = temperature = 435 K

R = gas constant = 8.314 J/K.mole

A = pre-exponential factor = $3.00\times 10^{+10}L/mol.s$

Now we have to calculate the value of rate constant by putting the given values in equation 1, we get:

$\ln (2.95\times 10^{-3}L/mol.s)=-\frac{Ea}{8.314J/K.mol\times 435K}+\ln (3.00\times 10^{10}L/mol.s)$

$Ea=108318.365J/mol=108.318kJ/mol$

Therefore, the value of activation energy for this reaction is 108.318 kJ/mol

3 0

3 years ago

A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper

finlep [7]

Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1: Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL * 0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene = 35.146 grams / 78 g/mol = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

Step 9: Calculate partial pressure

Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

Partial pressure of CCl4 = 0.5795 * 91.32 = 52.92 mmHg

Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

7 0

3 years ago

When the temperature of a rigid hollow sphere containing 685 L of helium gas is held at 621 K, the pressure of the gas is 1.89 x

Leno4ka [110]

You have to use the equation PV=nRT.
P=pressure (in this case 1.89x10^3 kPa which equals 18.35677 atm)
1V=volume (in this case 685L)
n=moles (in this case the unknown)
R=gas constant (0.08206 (L atm)/(mol K))
T=temperature (in this case 621 K)
with the given information you can rewrite the ideal gas law equation as n=PV/RT.
n=(18.35677atm x 685L)/(0.08206atmL/molK x 621K)
n=246.8 moles

8 0

3 years ago

If I have 5,000g of sodium, how much sodium sulfide can be made?

arlik [135]

2.469 could be maid dont forget to hit that thanks button

8 0

3 years ago

Read 2 more answers

Rozwiaz logogryf. Z wyróżnionych pól odczytaj hasło i je zapisz.

saul85 [17]

Answer:

1) Nitrogen

2) Methane

3) Dipeptide

4) Ammonia

5) Glycine

In Polish/Po polsku

1) Azot

2) metan

3) dipeptyd

4) Amoniak

5) glicyna

Explanation:

English Translation

Solve logogriffs. Read the password from the highlighted fields and write it down.

1.The chemical element being the main component of air (it occupies 78% of its volume),

2. The simplest saturated hydrocarbon,

3. Is a result of combining two amino acid molecules,

4. Gas with a pungent odor, soluble in water; hydrogen and nitrogen synthesis product.

5. Common name of aminoacetic acid

(the first has four boxes, the second has five boxes, the third has eight quarters has seven, fifths and seven).

Thank you in advance

1) The main component of air that makes up 78% of the air is Nitrogen.

2) The simplest saturated hydrocarbon is the first member of the alkane family, Methane.

3) Two amino acids combine by forming peptide bonds between the carboxyl group of one amino acid and the amino group of another through dehydration synthesis (loss of 1 molecule of water). Hence, the result of the combination of two amino acids are called Dipeptides.

4) Nitrogen and Hydrogen come together to form only one known water soluble gas with pungent smell, called Ammonia.

5) Aminoacetic acid as its name suggests is an amino acid with the acetyl group. It is the simplest amino acid. The common name for this compound is Glycine.

In Polish/Po polsku

1) Głównym składnikiem powietrza, które stanowi 78% powietrza, jest azot.

2) Najprostszym nasyconym węglowodorem jest pierwszy członek rodziny alkanów, metan.

3) Dwa aminokwasy łączą się, tworząc wiązania peptydowe między grupą karboksylową jednego aminokwasu i grupą aminową innego przez syntezę odwodnienia (utrata 1 cząsteczki wody). Stąd wynik połączenia dwóch aminokwasów nazywa się dipeptydami.

4) Azot i wodór tworzą razem jeden znany gaz rozpuszczalny w wodzie o ostrym zapachu, zwany amoniakiem.

5) Kwas aminooctowy, jak sama nazwa wskazuje, jest aminokwasem z grupą acetylową. To najprostszy aminokwas. Powszechna nazwa tego związku to glicyna.

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

8 0

3 years ago