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3 years ago

11

Phosphorus has three unpaired electrons and hydrogen has one unpaired electron this means that_____ equivalents of hydrogen can

react with ______ equivalents of phosphorus.

1 answer:

luda_lava [24]3 years ago

6 0

Three equivalents of hydrogen
One equivalent of phosphorus

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I really have no idea what to do here sorry. Help please.

horrorfan [7]

1. An ion is a charged atom. A molecule is a neutrally-charged combination of atoms.

2. A molecule is a combination of atoms. It can consist of atoms from one or more elements. For example, an oxygen molecule comprises two oxygen atoms. A compound is a substance made up of a combination of atoms of different elements. For example, water is a compound of hydrogen and oxygen.

3. An electron dot diagram is a simple way of representing the bond and electronic structure of molecules. A formula is a written representation of the types and numbers of atoms in a molecule.

4. As above...a formula denotes which atoms are in a molecule and how many. For example, H2SO4 tells us there are two hydrogen atoms, one sulfur atom and four oxygen atoms in each molecule of sulfuric acid.

5. An ionic bond is a type of chemical bond that stems from electrostatic attraction between ions with opposite charges. A covalent bond is another type of chemical bond that involves sharing of electrons between atoms in order to achieve a stable electronic structure for the molecule as a whole.

5 0

3 years ago

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

7 0

3 years ago

Sodium tert-butoxide (NaOC(CH3)3) is classified as bulky and acts as Bronsted Lowry base in the reaction. It is reacted with 2-c

IceJOKER [234]

Answer:but-1-ene

Explanation:This is an E2 elimination reaction .

Kindly refer the attachment for complete reaction and products.

Sodium tert-butoxide is a bulky base and hence cannot approach the substrate 2-chlorobutane from the more substituted end and hence major product formed here would not be following zaitsev rule of elimination reaction.

Sodium tert-butoxide would approach from the less hindered side that is through the primary centre and hence would lead to the formation of 1-butene .The major product formed in this reaction would be 1-butene .

As the mechanism of the reaction is E-2 so it will be a concerted mechanism and as sodium tert-butoxide will start abstracting the primary hydrogen through the less hindered side simultaneously chlorine will start leaving. As the steric repulsion in this case is less hence the transition state is relatively stabilised and leads to the formation of a kinetic product 1-butene.

Kinetic product are formed when reactions are dependent upon rate and not on thermodynamical stability.

2-butene is more thermodynamically6 stable as compared to 1-butene

The major product formed does not follow the zaitsev rule of forming a more substituted alkene as sodium tert-butoxide cannot approach to abstract the secondary proton due to steric hindrance.

5 0

3 years ago

Avanti works in a bookstore. She has four books and is going to place them in two stacks. The diagram above shows the books befo

Feliz [49]

Answer:

Well they didn't transfer any energy when they weren’t touching and it did t produce any energy if it didn’t move. Since they are on top of each other they are causing momentum on each other creating kinetic energy

Explanation:

3 0

2 years ago

All BUT one factor contributes to natural selection. That factor is

Juli2301 [7.4K]

<span>the one that is not a factor that contribute to natural selection is : Population stability population refer to the capability of a community to maintain its total amount of organisms within a specific period of time. This has nothing to do with natural selection, which basically a nature's way to reduce the number of organism to findout which organisms are more adaptive</span>

7 0

3 years ago

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