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2 years ago

Write a summary explaining how photosynthesis is occurring in this drawing

Chemistry

2 answers:

Virty [35]2 years ago

7 0

Answer:

In the picture, it's shown that the energy from the sun and carbon dioxide is absorbed by plants through the leaf and is used for cooking food in plants. It is also shown that nutrients and water needed for the plant is absorbed through the roots of the plant. And it's also shown that cooking results in the formation of Glucose and Oxygen in which oxygen is released into the atmospehere and the glucose is stored in the plant for its own needs.

Galina-37 [17]2 years ago

7 0

Answer:

In the picture, it's shown that the energy from the sun and carbon dioxide is absorbed by plants through the leaf and is used for cooking food in plants. It is also shown that nutrients and water needed for the plant is absorbed through the roots of the plant. And it's also shown that cooking results in the formation of Glucose and Oxygen in which oxygen is released into the atmospehere and the glucose is stored in the plant for its own needs.

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Which of these best describe a flight that is approaching the speed of sound

frozen [14]

Answer:

more drag is created because the air molecules are not moving out of the way of the airplane

Explanation:

7 0

2 years ago

Calculate ΔrG∘ at 298 K for the following reactions.CO(g)+H2O(g)→H2(g)+CO2(g)2-Predict the effect on ΔrG∘ of lowering the temper

KonstantinChe [14]

Answer:

1) ΔG°r(298 K) = - 28.619 KJ/mol

2) ΔG°r will decrease with decreasing temperature

Explanation:

CO(g) + H2O(g) → H2(g) + CO2(g)

1) ΔG°r = ∑νiΔG°f,i

⇒ ΔG°r(298 K) = ΔG°CO2(g) + ΔG°H2(g) - ΔG°H2O(g) - ΔG°CO(g)

from literature, T = 298 K:

∴ ΔG°CO2(g) = - 394.359 KJ/mol

∴ ΔG°CO(g) = - 137.152 KJ/mol

∴ ΔG°H2(g) = 0 KJ/mol........pure substance

∴ ΔG°H2O(g) = - 228.588 KJ/mol

⇒ ΔG°r(298 K) = - 394.359 KJ/mol + 0 KJ/mol - ( - 228.588 KJ/mol ) - ( - 137.152 KJ7mol )

⇒ ΔG°r(298 K) = - 28.619 KJ/mol

2) K = e∧(-ΔG°/RT)

∴ R = 8.314 E-3 KJ/K.mol

∴ T = 298 K

⇒ K = e∧(-28.619/(8.314 E-3)(298) = 9.624 E-6

⇒ ΔG°r = - RTLnK

If T (↓) ⇒ ΔG°r (↓)

assuming T = 200 K

⇒ ΔG°r(200 K) = - (8.314 E-3)(200)Ln(9.624E-3)

⇒ ΔG°r (200K) = - 19.207 KJ/mol < ΔG°r(298 K) = - 28.619 KJ/mol

6 0

2 years ago

Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.

Serjik [45]

I think the correct answer would be the last one.

7 0

2 years ago

Read 2 more answers

Calculate the number of moles of sulfuric acid in the total volume you used in the lab (i.e., 8.00 mL). Hint: Use the methodolog

insens350 [35]

Answer:

0.147 mol

Explanation:

Step 1: Calculate the volumetric concentration (Cv)

We will use the following expression.

Cv = Cg × ρ

Cv = 98.0 g%g × 1.84 g/mL = 180 g%mL

Step 2: Calculate the molarity of sulfuric acid

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

M = 180 g / 98.08 g/mol × 0.100 L = 18.4 M

Step 3: Calculate the moles of solute in 8.00 mL of solution

8.00 × 10⁻³ L × 18.4 mol/L = 0.147 mol

4 0

2 years ago

If it requires 75.0mL of 0.500M NaOH to neutralize 165.0 mL of an hcl solution what is the concentration of the hcl solution

Kaylis [27]

Answer:

0.027 M HCl

Explanation:

The chemical equation of the neutralization is:

1 NaOH + 1 HCl -> 1 H2O + 1 NaCl

Because the ratio of NaOH and HCl is 1:1 you can use the M1V1=M2V2 formula.

(75 mL)(0.5 M NaOH) = (165 mL)(M HCl)

It requires 0.027 M HCl.

7 0

2 years ago