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3 years ago

Write a summary explaining how photosynthesis is occurring in this drawing

Chemistry

2 answers:

Virty [35]3 years ago

7 0

Answer:

In the picture, it's shown that the energy from the sun and carbon dioxide is absorbed by plants through the leaf and is used for cooking food in plants. It is also shown that nutrients and water needed for the plant is absorbed through the roots of the plant. And it's also shown that cooking results in the formation of Glucose and Oxygen in which oxygen is released into the atmospehere and the glucose is stored in the plant for its own needs.

Galina-37 [17]3 years ago

7 0

Answer:

In the picture, it's shown that the energy from the sun and carbon dioxide is absorbed by plants through the leaf and is used for cooking food in plants. It is also shown that nutrients and water needed for the plant is absorbed through the roots of the plant. And it's also shown that cooking results in the formation of Glucose and Oxygen in which oxygen is released into the atmospehere and the glucose is stored in the plant for its own needs.

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A stock bottle of an acid reads: 56% by mass and 1.25 specific gravity. If the molar mass of the acid is 70g, find the mole per

TiliK225 [7]

Answer:

10 mol / dm³

Explanation:

Cubic decimeter is the same unit as liter; so, mole per cubic decimeter is mole per liter, and that is the unit of concentration of molarity. Thus, what is asked is the molarity of the solution. This is how you find it.

1. Take a basis: 1 dm³ = 1 liter = 1,000 ml

2. Calculate the mass of 1 liter (1,000 ml) of solution:

density = mass / volume ⇒ mass = density × volume

Here, the density is given through the specific gravity

Scpecific gravity = density of acid / density of water

Take density of water as 1.00 g/ml.

density of solution = 1.25 g/ml

mass solution = 1.25 g/ml × 1,000 ml = 1,250 g

3. Calculate the mass of solute (pure acid)

% m/m = (mass of solute / mass of solution) × 100

56 = mass of solute / 1,250 g × 100

mass of solute = 56 × 1,250g / 100 = 700 g

4. Calculate the number of moles of solute:

moles = mass in grams / molar mass = 700 g / 70 g/mol = 10 mol

5. Calculate molarity (mol / dm³)

M = number of moles of solute / liter of solution = 10 mol / 1 liter = 10 mol/liter.

5 0

3 years ago

What will happen if a crystal of ammonium nitrate is added to a supersaturated ammonium nitrate solution? Will it dissolve in wa

romanna [79]

Answer:

It will not dissolve. More crystals will separate from the solution.

Step-by-step explanation:

If you add a crystal of ammonium nitrate to a supersaturated solution of the solute, it will not dissolve.

Instead, it will act as a "seed" on which more ammonium nitrate crystals will form.

They will separate from the solution as long, colourless, needle-like crystals until the solution is no longer supersaturated.

5 0

3 years ago

Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas

hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Suppose 1.20 mol $CS_2(g)$ of and 3.60 mol of $Cl_2(g)$ were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol of $CCl_4$ . Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of $CS_2$ = 1.20 mole

Moles of $Cl_2$ = 3.60 mole

Volume of solution = 1.00 L

Initial concentration of $CS_2$ = $\frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M$

Initial concentration of $Cl_2$ = $\frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M$

The given balanced equilibrium reaction is,

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Initial conc. 1.20 M 3.60 M 0 0

At eqm. conc. (1.20-x) M (3.60-3x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}$

Given :Equilibrium concentration of $CCl_4$ , x = $\frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M$

$K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}$

$K_c=0.36$

Thus equilibrium constant at unknown temperature is 0.36

4 0

3 years ago

Balance the following equations:

neonofarm [45]

Hope this helps! If you dont understand balancing equations in general, say so in the comments, I’m happy to help

7 0

3 years ago

92dm3 of a gas dissolved in a solvent. How many moles is this?

Paul [167]

Assuming its at r. t.p and pressure
no. of moles = 96/24=4moles
altho some books will say that its 23.7dm3/mole but that doesnt really matter because its the process that matters

5 0

3 years ago