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The solution to the above factorization problem is given as f′(x)=4x³−3x²−10x−1. See steps below.
<h3>What are the steps to the above answer?</h3>Step 1 - Take the derivative of both sides
f′(x)=d/dx(x^4−x^3−5x^2−x−6)
Step 2 - Use differentiation rule d/dx(f(x)±g(x))=d/dx(f(x))±d/dx(g(x))
f′(x)=d/dx(x4)−d/dx(x^3)−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−d/dx(x3)−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x2−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x^2−10x−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x^2−10x−1−dxd(6)
f′(x)=4x^3−3x^2−10x−1−0
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If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
Given that a number plate can be formed using 2 alphabets which must come in increasing order.
We are required to find the number of plates that can be formed.
Number of total alphabets=26.
The number of plates will be equal to the number of ways in which two alphabets can be arranged.
Combination is the number of ways in which some combinations can be formed. It is expressed as n=n!/r!(n-r)!
Number of license plates=26*25
=26*25
=650 plates
Hence If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
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