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3 years ago

The table below shows the ticket rates for whale watching trips offered by Ocean Tours:

1 answer:

6 0

For finding the solution, you want to sum the revenue from each class of paying customers. There were 92-40 who were over 12 years and paid $48, so the revenue from those folks is (92-40)·48. This term is found in the first and last selections only.

There were 40-x customers who were in the age range 3–12 years, so paid $36 each. The revenue from them is (40-x)·36. This term is found in the last selection only.

The appropriate choice is ...

... D.) (40 - x)·36 +(92 - 40)·48 = C

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Find a “solution” for an equation with two variables. Tell me an x, y ordered pair that is a solution (answer) for this equation

Finger [1]

Answer:

Step-by-step explanation:

A graph has a constant of proportionality of 7.2. Let y represent minutes and x represent miles.

What is the unit rate of the relationship?

Enter your answer, as a decimal, in the box

min/mi

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4 0

3 years ago

Please answer my question below Will give you a brainliest?

VARVARA [1.3K]

Answer:

1: 3\sqrt2 - \sqrt14

2: \sqrt21 - 2\sqrt(7)

3: 4\sqrt3 - \sqrt15

4: 2\sqrt5 - \sqrt10

5: -3 + 3\sqrt5

I already gave you these answers man

Step-by-step explanation:

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3 years ago

Find two acute angles that satisfy the equation sin(2x + 7) = cos(x + 23). Check that your answers make

Vera_Pavlovna [14]

Answer:

The smaller angle is 43 and the larger angle is 47

Step-by-step explanation:

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2 years ago

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

3 years ago

How many fixed-requirement constraints does a transportation problem with 5 factories and 6 customers have?a. 30.b. 11.c. 6.d. 5

bulgar [2K]

Answer:

Option B

Step-by-step explanation:

From the question we are told that:

Demand point $m=5$

Supply Point $n=6$

Generally the equation for fixed-requirement constraints is mathematically given by

$X=m+n$

$X=5+6$

$X=11$

Therefore the correct option is

Option B

7 0

2 years ago